Answer:
100% of the 2nd monthly payment go toward the repayment of principal.
Step-by-step explanation:
The loan taken is the Principal which is mentioned as $72,500 with interest at a nominal rate of 20%. Firstly, it is important to understand that nominal rate means <em>non-compounding </em>rate. Simply put will be a "<em>one-time charged" </em>rate on the loan. Since this is given as 20% of the Principal. It is calculated thus: 
× 
= $14,500. So the interest on the loan is $14,500. Added to the Principal the total amount to be paid back by the company becomes: $72,500 + $14,500 = $87,000. To pay back this amount at equal end-of-month installments in 1 year (12 months), we divide the total amount by 12. i.e 
= $7250. This means, the monthly payment will be $7,250. Since the monthly payment pays only 10% of the initial principal $72,500. By the second month only 20% of the Principal would have been paid. So all of the monthly payment will go towards repaying the principal
Answer:
B. (3, 0)
Step-by-step explanation:
The x-intercept is the point where the graph of the function meets the x-axis.
At x-intercept, y=0 or f(x)=0
So look through the table and find where f(x)=0.
From the table, f(x)=0 at x=3.
We write this as an ordered pair.
Therefore the x-intercept is (3,0)
The correct choice is B.
Answer:
2000 players will complete the game with a perfect score.
Step-by-step explanation:
The testing phase tells us that 
is the probability that a person will finish with a perfect score.
This means 1 out of 500 people will be able to finish with perfect score.
Now,
the game is given to 1,000,000 (1 million) people and how much do we expect to finish with perfect score?? Simple! It would be the of 1 million!
We do the calculation shown below:
So, 2000 players will complete the game with a perfect score.
Answer:
Option b
Step-by-step explanation:
Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.
Expected observed Diff
x p(x) p(x)*1000
0 0.002 2
1 0.011 11 14 -3
2 0.115 115 15 100
3 0.123 123 130 -7
4 0.144 144
5 0.189 189
6 0.238 238
7 0.178 178
1 1000
We find that there is a large difference in 2 job application
Hence option b is right.
