For this case we have the following inequality: y < 3x + 1 < br/ >
What we must do is to evaluate a point of the Cartesian plane and verify if it is in the shaded region.
The shaded region represents the solution of the system of equations.
For the point (0, 0) we have:
0 < 3(0) + 1 < br / >
0 < 0 + 1 < br / >
0 < 1 < br / >
Therefore, the point (0, 0) is in the shaded region because it satisfies the inequality.
Then, the points that are on the line, are not part of the solution because the sign is of less strict.
Hope I helped ~~Laurel
D. 16 clusters
Hope it helps
Answer:
Step-by-step explanation:
given are four statements and we have to find whether true or false.
.1 If two matrices are equivalent, then one can be transformed into the other with a sequence of elementary row operations.
True
2.Different sequences of row operations can lead to different echelon forms for the same matrix.
True in whatever way we do the reduced form would be equivalent matrices
3.Different sequences of row operations can lead to different reduced echelon forms for the same matrix.
False the resulting matrices would be equivalent.
4.If a linear system has four equations and seven variables, then it must have infinitely many solutions.
True, because variables are more than equations. So parametric solutions infinite only is possible
Answer:
SD = 7588.09
Step-by-step explanation:
Check the distribution table attached to for the step by step solution:
The formula for the mean, 
The variance , 
Standard Deviation,
SD = 7588.09
Answer:
The correct answer is
(0.0128, 0.0532)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence interval 
, we have the following confidence interval of proportions.
In which
Z is the zscore that has a pvalue of 
For this problem, we have that:
In a random sample of 300 circuits, 10 are defective. This means that 
and 
Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.
So 
= 0.05, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The correct answer is
(0.0128, 0.0532)
