It looks like you're given
Then by the additivity of definite integrals this is the same as
(presumably this is what the hint suggests to use)
Then by the fundamental theorem of calculus, we have
Julie is selling candy bars to raise money for new band uniforms. Candy bar X sells for $2 and candy bar Y sells for $3. Julie n
2 answers:
Answer:
Answer is C
Step-by-step explanation:
Selling price of candy bar X =$2
Selling price of candy bar Y =$3
So if Julie sells x from X candy bars and y bars from Y candy bars,
Profit made from selling X candy bars =
Profit made from selling Y candy bars =
Therefore, assuming that there is no cost for the candy bars the profit by selling candy bars can be represented by the following objective function:
Therefore, answer is C
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Answer:
Step-by-step explanation:
Hello!
For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.
In this example the variable is:
X: height of a college student. (cm)
There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.
The option you have is to apply the Central Limit Theorem.
The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.
As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.
The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:
X[bar]~~N(μ;σ2/n)
Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:
98% CI
1 - α: 0.98
⇒α: 0.02
α/2: 0.01
X[bar] ±
174.5 ±
[172.22; 176.78]
With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].
I hope it helps!