Given the graph below, which of the following statements is true? On a coordinate plane, a graph shows an image with three conne
cted lines. The first line has a negative slope and goes from (negative 5, 6) to (negative 2, 0), the second line has a positive slope and goes from (negative 2, 0) to (2, 2), and the third line has a negative slope going from (2, 2) through (4, negative 2). The graph represents a one-to-one function because every x-value is paired with only one y-value. The graph represents a one-to-one function because it is defined for all x-values. The graph does not represent a one-to-one function because it does not pass through the origin. The graph does not represent a one-to-one function because the y-values between 0 and 2 are paired with multiple x-values.
2 answers:
Answer:
The correct option is (D).
Step-by-step explanation:
A one-to-one function can be defined such the every value of <em>x</em> corresponds to exactly one value of <em>y</em>.
That is:
x₁ → y₁
x₂ → y₂
x₃ → y₃
.
.
.
and so on.
Consider the graph.
From the graph it can be seen that for <em>y</em> = 0 and <em>y = </em>2 there are multiple <em>x</em> coordinates.
So, the graph does not represent a one-to-one function because the y-values between 0 and 2 are paired with multiple x-values.
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Hello,
y=5+3*cos (2(x-π/3))
The function is periodic with periode=2π.
-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8
y=5+3*cos (2(x-π/3))
The function is periodic with periode=2π.
-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8
Complete question:
The line graph relating to the question was not attached. However, the line graph has can be found in the attachment below.
Answer:
17,209
Step-by-step explanation:
The line graph provides information about alcohol-related highway fatalities between year 2001 to 2010.
Determine the average number of alcohol-related fatalities from 2001 to 2006. Round to the nearest whole number.
The average number of alcohol related fatalities between 2001 - 2006 can be calculated thus :
From the graph:
Year - - - - - - - - - - Number of fatalities
2001 - - - - - - - - - - 17401
2002 - - - - - - - - - 17525
2003 - - - - - - - - - 17013
2004 - - - - - - - - - 16694
2005 - - - - - - - - - 16885
2006 - - - - - - - - - 17738
To get the average :
Sum of fatalities / number of years
(17401 + 17525 + 17013 + 16694 + 16885 + 17738) / 6
= 103256 / 6
= 17209.333
Average number of alcohol related fatalities is 17,209 (to the nearest whole number)
