Given the graph below, which of the following statements is true? On a coordinate plane, a graph shows an image with three conne
cted lines. The first line has a negative slope and goes from (negative 5, 6) to (negative 2, 0), the second line has a positive slope and goes from (negative 2, 0) to (2, 2), and the third line has a negative slope going from (2, 2) through (4, negative 2). The graph represents a one-to-one function because every x-value is paired with only one y-value. The graph represents a one-to-one function because it is defined for all x-values. The graph does not represent a one-to-one function because it does not pass through the origin. The graph does not represent a one-to-one function because the y-values between 0 and 2 are paired with multiple x-values.
2 answers:
Answer:
The correct option is (D).
Step-by-step explanation:
A one-to-one function can be defined such the every value of <em>x</em> corresponds to exactly one value of <em>y</em>.
That is:
x₁ → y₁
x₂ → y₂
x₃ → y₃
.
.
.
and so on.
Consider the graph.
From the graph it can be seen that for <em>y</em> = 0 and <em>y = </em>2 there are multiple <em>x</em> coordinates.
So, the graph does not represent a one-to-one function because the y-values between 0 and 2 are paired with multiple x-values.
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Answer:
32, 37, 42, 47, 52, 57, 62.
Step-by-step explanation:
It is given that Carissa counts by 5s from 32 to 62.
It means, we have to add 5 in the number to get the next number.
Add 5 in 32.
Now, add 5 in 37.
Similarly, continue the process.
Therefore, the numbers counted by carissa are 32, 37, 42, 47, 52, 57, 62.
Answer:
alternate interior angles theorem
Step-by-step explanation:
The alternate interior angles theorem states that when two parallel lines are cut by a transversal, the resulting angles produced are a pair of congruent alternate interior angles.
Given the image attached below, both line k and line l are parallel to each other and also, line t is the transversal, therefore the resulting congruent alternate interior angles produced are:
∠ 4 ≅ ∠6, ∠1 ≅ ∠7
