Solution: We are given:
Total students = 10 + 30 + 10 =50
Number of students who received A grade = 3 + 10 + 5 = 18
Number of senior student's who received A grade is = 10
Let A be the event that the student is senior and B be the event that he or she earned an A. Then,


Now the probability a student chosen at random from this class and is found to have earned an A, the probability that he or she is a senior is:



Answer:
whole
Step-by-step explanation:
No question is posed.
If we assume we're interested in the number of cars sold on Monday, we have ...
part = percent × whole
14 = 56% × whole
It would seem that we're looking for the whole.
__
14/.56 = 25 cars were sold on Monday.
9x - 2y = 11 ... (i)
5x - 2y = 15 ... (ii)
Subtracting equation (ii) from (i) we get;
4x + 0 = -4
4x=-4 , x = -1
Replacing x = -1 in equation (i) we get;
9(-1) - 2y = 11
-9 - 2y = 11
-2y = 20
y = 20 ÷ -2 = -10
The solution to the system of equations is (-1,-10).
Answer:
B. (3, 0)
Step-by-step explanation:
The x-intercept is the point where the graph of the function meets the x-axis.
At x-intercept, y=0 or f(x)=0
So look through the table and find where f(x)=0.
From the table, f(x)=0 at x=3.
We write this as an ordered pair.
Therefore the x-intercept is (3,0)
The correct choice is B.
Answer:
-40 < t < 284
Step-by-step explanation:
The antifreeze protects the car between −40°C and 140°C.
Using t for temperature, the compound inequality of the Celsius temperature range is:
-40 < t < 140
The conversion formula is given to find degrees C in given degrees F. We can solve the formula for F, so we get degrees F in terms of degrees C.
C = (5/9)(F - 32) <------ <em>conversion formula from deg F to deg C</em>
Solve for F:
(9/5)C = F - 32
(9/5)C + 32 = F
F = (9/5)C + 32 <------ <em>conversion formula from deg C to deg F</em>
Now we convert -40 deg C to deg F using the formula we just derived.
F = (9/5)C + 32
F = (9/5)(-40) + 32
F = -72 + 32
F = -40
-40 deg C = -40 deg F
(This is not a mistake or a typo. -40 deg C really is the same as -40 deg F.)
Now we convert 140 deg C to deg F using the formula we just derived.
F = (9/5)C + 32
F = (9/5)(140) + 32
F = 252 + 32
F = 284
140 deg C = 284 deg F
Now we rewrite the compound inequality with Fahrenheit temperatures.
-40 < t < 284