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1 year ago

Identify the relative maximum value of g(x) for the function shown below g(x)=7/x^2+5

2 answers:

8 0

To find t<span>he relative maximum value of the function we need to find where the function has its first derivative equal to 0.

Its first derivative is -7*(2x)/(x^2+5)^2
</span>7*(2x)/(x^2+5)^2 =0 the numerator needs to be eqaul to 0
2x=0
x=0

g(0) = 7/5

The <span>relative maximum value is at the point (0, 7/5).</span>

Dahasolnce [82]1 year ago

8 0

On April ex the answer is 7/5

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Step-by-step explanation:

After one year

A=p(1+r/n)^nt

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=2000(1.0304)

=$2060.8

After two-years

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After three years

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2 years ago

will crown brainliest Stephanie puts 30 cubes in a box. The cubes are 1/2 inch on each side. The box holds two layers with 15 cu

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1 year ago

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Ethan bought 4 packages of pencils. After he gave 8 pencils to his friends, he had 40 pencils

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He had 40 pencils left after he gave away 8, so originally he had 40 + 8 pencils, which is 48.

Now, he bought 4 packages, which had a total of 48 pencils, so divide 48 by 4, which is 12. He had 12 pencils in each package.

To determine the solution arithmetically, first add 8 to 40, then divide 48 by 4.

To determine the solution algebraically, set up and solve the equation 40 = 4x - 8.

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2 years ago

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Answer:

One-way ANOVA

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1 year ago

Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

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Answer: The required inequality is $x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$ and its solution is $x>8.$

Step-by-step explanation: Given that Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Also, Heloise has written $\frac{1}{4}$ as many articles as Mustafa has and Gia has written $\frac{3}{2}$ as many articles as Mustafa has.

We are to write an inequality to determine the number of articles, m, Mustafa could have written for the school newspaper. Also, to solve the inequality.

Since m denotes the number of articles that Mustafa could have written. Then, according to the given information, we have

$x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$

And the solution of the above inequality is as follows :

$x+\dfrac{1}{4}x+\dfrac{3}{2}x>22\\\\\\\Rightarrow \dfrac{4x+x+6x}{4}>22\\\\\\\Rightarrow 11x>88\\\\\Rightarrow x>\dfrac{88}{11}\\\\\Rightarrow x>8.$

Thus, the required inequality is $x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$ and its solution is $x>8.$

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