Question

The height of a baseball thrown from the catcher to first base is modeled by the function h(t) = –0.09t2 + 0.72t + 6, where h is the height of the ball measured in feet and t is the time since being thrown, measured in seconds. The ball is in the air for 10 seconds before being caught. What's the height of the ball at 10 seconds?

Answer 1

The height of a baseball thrown from the catcher to first base is modeled by the function $h(t) = -0.09t^2 + 0.72t + 6$, where h is the height of the ball measured in feet and t is the time since being thrown, measured in seconds

To find out height of the ball at 10 seconds, we plug in 10 for t

$h(t) = -0.09t^2 + 0.72t + 6$

$h(10) = -0.09(10)^2 + 0.72(10) + 6$

h(10)=4.2 feet

the height of the ball at 10 seconds= 4.2 feet