Suppose we have two thermometers. One thermometer is very precise but is delicate and heavy (X). We have another thermometer tha
t is much cheaper and lighter, but of unknown precision (Y). We would like to know if we can (reliably) bring the lighter thermometer with us into the field. So, we set up an experiment where we expose both thermometers to 31 different temperatures and measure the temperature with each.
We get the following observations:
x = 0, 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100, 104, 108, 112, 116, 120
y = 0.02, 3.99, 7.91, 12.03, 16.09, 20.00, 23.98, 28.09, 31.94, 36.03, 40.00, 44.05, 47.95, 52.00, 55.87, 59.90, 63.91, 67.95, 72.11, 76.02, 80.01, 84.10, 88.06, 91.74, 96.02, 99.95, 103.87, 108.01, 111.99, 116.04, 120.03
We want to test if these thermometers seem to be measuring the same temperatures. Let's use the threshold α=0.1.
Answer all questions up to 3 decimals
(a) Write down the appropriate hypothesis tests for β1.
H0: β1(≠ / = / > / <) 1 and Ha: β1( ≤ / = / > / ≠ / ≥ / <) 1.
(b) The test statistic is _____. (Use 2 decimal places)
(c) The p-value is _____. (Use 4 decimal places)
We get the following observations:
x = 0, 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100, 104, 108, 112, 116, 120
y = 0.02, 3.99, 7.91, 12.03, 16.09, 20.00, 23.98, 28.09, 31.94, 36.03, 40.00, 44.05, 47.95, 52.00, 55.87, 59.90, 63.91, 67.95, 72.11, 76.02, 80.01, 84.10, 88.06, 91.74, 96.02, 99.95, 103.87, 108.01, 111.99, 116.04, 120.03
We want to test if these thermometers seem to be measuring the same temperatures. Let's use the threshold α=0.1.
Answer all questions up to 3 decimals
(a) Write down the appropriate hypothesis tests for β1.
H0: β1(≠ / = / > / <) 1 and Ha: β1( ≤ / = / > / ≠ / ≥ / <) 1.
(b) The test statistic is _____. (Use 2 decimal places)
(c) The p-value is _____. (Use 4 decimal places)
1 answer:
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Answer:
40 cm
Step-by-step explanation:
Using the conversion
1 litre = 1000 cm³, then
40 litres = 40 × 1000 = 40000 cm³
The volume ( V) of a cuboid is
V = lbh ( divide both sides by bh )
l = =
=
= 40 cm
Answer:
The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph
Step-by-step explanation:
we know that
The speed is equal to divide the distance by the time
Let
x -----> the speed of the wind in miles per hour
y ----> the speed of the jet in still air in miles per hour
we know that
<em>With a tailwind</em>
----> equation A
<em>With a headwind</em>
----> equation B
solve the system of equations A and B by elimination
Adds equation A and equation B
<em>Find the value of x</em>
therefore
The speed of the jet in still air is 415 mph and the speed of the wind is 19 mph
Answer:
12th term would be -26.
Step-by-step explanation:
Given explicit formula of a sequence,
Where,
n = number of a term.
i.e. 12th term will get after putting n = 12 in the formula.
Hence, 12th term of the sequence would be,