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gulaghasi [49]
1 year ago
13

Dina and Masha started out on a 20 miles bike path at the same time. When Dina reached the end of the 20 miles, Masha still had

4 miles left to bike. If Dina’s biking speed was 10 mph, find Masha’s biking speed.
Mathematics
2 answers:
leonid [27]1 year ago
4 0

Answer:

8mph

Step-by-step explanation:

(20-4)/2

=16/2

=8

Bingel [31]1 year ago
3 0

Answer:

8

Step-by-step explanation:

(20-4)/2=16/2=8

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Simplify the square root of four over the cubed root of four. four raised to the five sixths power four raised to the one sixth
romanna [79]

Answer:

(B)4^{1/6}

Four raised to the one-sixth power

Step-by-step explanation:

We want to simplify:  \dfrac{\sqrt{4} }{\sqrt[3]{4} }

First, we apply the fractional law of indices to each term.

\text{If  } a^{1/x}=\sqrt[x]{a},$ then:\\\sqrt{4}=4^{1/2}\\\sqrt[3]{4}=4^{1/3}

We then have:

\dfrac{\sqrt{4} }{\sqrt[3]{4} }=\dfrac{4^{1/2} }{4^{1/3} }\\$Applying the division law of indices: \dfrac{a^m }{a^n }=a^{m-n}\\\dfrac{4^{1/2} }{4^{1/3} }=4^{1/2-1/3}\\\\=4^{1/6}

The correct option is B.

7 0
1 year ago
Eric works for an airline, and he needs to calculate the weight of passengers and luggage before takeoff. The number of
igomit [66]

Answer:

B

Step-by-step explanation:

To complete the question, here are the answer choices:

<em>A)  =A1*A2*A3*A4 </em>

<em>B)  =A1*A2+A3+A1*A4 </em>

<em>C)  =A1*(A2+A3+A1)*A4 </em>

<em>D)  =A1*A2+(A3+A1)*A4</em>

<em />

We first need to multiply A1 and A2, this will give weight of passengers.

To get weight of luggage, we multiply A1 and A4.

We also need the checked weight to add to that, which is in A3. So then we add up A3 with those 2.

So we will get

A1*A2 + A1*A4 + A3

This is given in a different order in Option B. Hence, option B is right.

4 0
2 years ago
Read 2 more answers
For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
1 year ago
Read 2 more answers
Which number line represents the following statement?<br><br> A number is more than negative five.
jarptica [38.1K]
Number Line A, well the first number line.

The open circle shows us that -5 is NOT in the solution. All the numbers greater than -5 ( x > -5) are in the solution.

Faith xoxo
3 0
1 year ago
Read 2 more answers
The square of a number decreased by 3 times the number 28 find all possible values for the number
stealth61 [152]

Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number  

Answer:

The possible values of number are 7 and -4

Solution:

Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

From given information,

square of a number decreased by 3 times the number = 28

a^2 - 3a = 28

a^2 - 3a - 28 = 0

Let us solve the above quadratic equation

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

\text { For } a^{2}-3 a-28=0 \text { we have } a=1, b=-3, c=-28

\begin{aligned}&a=\frac{-(-3) \pm \sqrt{(-3)^{2}-4(1)(-28)}}{2 \times 1}\\\\&a=\frac{3 \pm \sqrt{9+112}}{2}\\\\&a=\frac{3 \pm \sqrt{121}}{2}=\frac{3 \pm 11}{2}\\\\&a=\frac{3+11}{2} \text { or } a=\frac{3-11}{2}\\\\&a=7 \text { or } a=-4\end{aligned}

Thus the possible values of number are 7 and -4

5 0
1 year ago
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