Damien , Jake , and Makayla shared a bowl of grapes . Damien ate x grapes . Jake ate 1 more than twice the number of grapes that
2 answers:
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Answer:
1) The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Step-by-step explanation:
Given : Assume there are 365 days in a year.
To find : 1) What is the probability that ten students in a class have different birthdays?
2) What is the probability that among ten students in a class, at least two of them share a birthday?
Solution :
Total outcome = 365
1) Probability that ten students in a class have different birthdays is
The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...
The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday
P(2 born on same day) = 1- P( 2 not born on same day)
The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Answer:
Step-by-step explanation:
We are given that 30% of California residents have adequate earthquake supplies.
a) Ramon variable X denotes the number of the california residents that have adequate earthquake insurance
B) x can take value 1 ,2 ,3 ......
C)The distribution of random variable is geometric distribution with parameter p=0.3
The pmf of geometric distribution is
D)P(X=1) or P(X=2)=P(X=1)+P(X=2)
P(X=1) or P(X=2)=
E)
F)
p is the resident who does not have adequate earthquake supplies.
p = 1-0.3 = 0.7
G)