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Aleks [24]
2 years ago
5

1/2(6+3p)-3/4(8-10p)Expand and simplify show all steps

Mathematics
1 answer:
olganol [36]2 years ago
7 0
\frac{6+3p}{2} -  \frac{3}{4} (8 - 10p) \\ \\  \frac{6 + 3p}{2} -  \frac{3(8-10p)}{4} \\ \\   \frac{6+3p}{2} -  \frac{3 \times 2(4 - 5p)}{4} \\ \\  \frac{6+3p}{2} -  \frac{6(4-5p)}{4} \\ \\  \frac{6+3p}{2} -  \frac{3(4-5p)}{2}  \\ \\  \frac{6+3p - 3(4-5p)}{2} \\ \\   \frac{3(2 +p - 4 + 5p}{2} \\ \\  \frac{3(2 + (p + 5p) - 4)}{2} \\ \\  \frac{3(2+6p-4)}{2} \\ \\  \frac{3 \times 2 (1 + 3p-2)}{2} \\ \\  \frac{3 \times 2(3p - 1)}{2} \\ \\  \frac{6(3p -1 }{2} \\ \\ 3(3p - 1) \\ \\ Answer: \fbox {3(3p-1)}
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Shelley receives supplies for her sno-cones business weekly. She usually works concession at four events a week and averages sal
My name is Ann [436]

Answer:

<u>Shelley did not budget enough. She will need additional US$ 16 for fulfilling the average sales of 760 sno-cones at the 4 events. With the budget she has, she just can supply 714 sno-cones (250 / 0.35).</u>

Step-by-step explanation:

1. Let's check all the information given for solving this question:

Cost of individual supply = US$ 0.35

Budget per week = US$ 250

Average sales of sno-cones per event = 190

Number of events per week = 4

2. Let's check if Shelley budgeted enough for the week events:

Total of sno-cones Shelley will sell = Average sales * Number of Events

Total of sno-cones Shelley will sell = 190 * 4 = 760

Cost of supplies for the week = Total of sno-cones * Cost of individual supply

Cost of supplies for the week = 760 * 0.35 = US$ 266

Budget per week = US$ 250

Budget per week  - Cost of supplies for the week = 250 - 266 = - 16

<u>Shelley did not budget enough. She will need additional US$ 16 for fulfilling the average sales of 760 sno-cones at the 4 events. With the budget she has, she just can supply 714 sno-cones (250 / 0.35).</u>

4 0
2 years ago
Marcus pours 12 ounces of cranberry juice into a punch bowl. He uses a container to add sprakling water to the bowl one ounce at
melomori [17]

Answer: There is 20 ounces of liquid in the bowl after adding 8 containers of sparkling water.

Step-by-step explanation:

Since we have given that

Number of ounces of cranberry juice into a punch bowl = 12 ounces

According to question, he uses a container to add sparkling water to the bowl one ounce at a time.

Let the amount of sparkling water added to the bowl be 'x'

Let the total number of ounces of liquid Marcus will have be 'y'.

So, our equation becomes,

y=12+x

Here, we have asked after adding 8 containers of sparkling water .

So, now, our equation becomes,

y=12+x\\\\y=12+8\\\\y=20\ ounces

Hence, there is 20 ounces of liquid in the bowl after adding 8 containers of sparkling water.

6 0
1 year ago
A freezer has a temperature of 14 degrees Fahrenheit. An ice-cube tray full of water is placed in the freezer. The function f(t)
Hitman42 [59]

Answer:

  65

Step-by-step explanation:

You can use f(15) = 40 to solve for C, then find f(0), the initial temperature.

  40 = f(15)

  40 = Ce^(-0.045·15) +14 = .50916C +14

  26 = .50916C

  26/.50916 = C ≈ 51.065

Then f(0) is ...

  f(0) = 51.065·e^0 +14 = 65.065 ≈ 65

The initial temperature of the water was 65 degrees Fahrenheit.

5 0
2 years ago
Read 2 more answers
A principal of $2000 is placed in a savings account at 3% per annum compounded annually. How much is in the account after one ye
natita [175]

Answer:

Step-by-step explanation:

After one year

A=p(1+r/n)^nt

=2000(1+0.03/12)^12*1

=2000(1+0.0025)^12

=2000(1.0025)^12

=2000(1.0304)

=$2060.8

After two-years

A=p(1+r/n)^nt

=2060.8(1+0.03/12)^12*2

=2060.8(1+0.0025)^24

=2060.8(1.0025)^24

=2060.8(1.0618)

=$2188.157

After three years

A=p(1+r/n)^nt

=2188.157(1+0.03/12)^12*3

=2188.157(1+0.0025)^36

=2188.157(1.0025)^36

=2188.157(1.0941)

=$2394.063

8 0
2 years ago
In a circle with center C and radius 6, minor arc AB has a length of 4pi. What is the measure, in radians, of central angle ACB?
valina [46]
To solve this problem, we need to know that 
arc length = r &theta;  where &theta; is the central angle in radians.

We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, &theta;
Rearrange equation at the beginning,
&theta; = (arc length) / r = 4pi / 6 = 2pi /3

Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees
8 0
2 years ago
Read 2 more answers
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