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Katena32 [7]
2 years ago
6

There are 520 marbles in a jar. The ratio of red to yellow marbles is 3:4 and the ratio of yellow to blue marbles is 2:3. What i

s the total number of yellow and blue marbles?
Mathematics
1 answer:
frutty [35]2 years ago
7 0

Answer:

Step-by-step explanation:

Change the 2/3 to 4/6

Now the ratio becomes 3:4:6

So the number of each is

3x + 4x + 6x = 520

13x = 520

x = 40

Red = 3*40 =      120

Yellow = 4*40 = 160

Blue = 6 * 40  = 240

Total =               520

You might be interested in
What is the nth term of this sequence 7, 9, 11, 13
Alexus [3.1K]

Answer:

The nth term of the sequence is

<h2>5 + 2n</h2>

Step-by-step explanation:

The sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

From the question

a = 7

d = 9 - 7 = 2 or 11 - 9 = 2

So the nth term for the sequence is

A(n) = 7 + ( n - 1)2

= 7 + 2n - 2

<h3>A(n) = 5 + 2n</h3>

Hope this helps you

5 0
2 years ago
Read 2 more answers
In two or more complete sentences explain how you would set up and solve the following equation: Peter opened his account with $
Black_prince [1.1K]
Peter will have $910 - $40 * x on his account, where x is the number of the weeks. Marla will have $470 - $20 * x.
910 - 40 x = 470 - 20 x
910 - 470 = 40 x - 20 x
440 = 20 x
x = 440 : 20
x = 22
910 - 40 * 22 = 910 - 880 = $30
470 - 20 * 22 = 470 - 440 = $30
Answer: Their accounts will be equal in 22 weeks ( both of them will have $30 ).
3 0
2 years ago
In high-school 135 freshmen were interviewed.
timama [110]

Answer:

a) n(none) = 25

b) n(PE but not Bio) = 25

c) n(ENG but not both BIO and PE) = 55

d) n(students that did not take Eng or Bio) = 40

e) P( Students did not take exactly two subjects) = 0.65

Step-by-step explanation:

From the Venn diagram drawn:

a) Number of students that took none

n(Freshmen) = 135

n(all three) = 5

n (PE and Bio) = 10

n(PE and Eng) = 15

n(Bio and Eng) = 7

n (PE and Bio only) = 10 - 5 = 5

n(PE and Eng only) = 15 - 5 = 10

n(Bio and Eng only) = 7 - 5 = 2

n(PE only) = 35 - 5 - 5 - 10 = 15

n(Bio only) = 42 - 5 - 5 - 2 = 30

n(Eng only) = 60 - 10 - 5 -2 = 43

n(Freshmen) = n(PE only) + n(Bio only) + n(Eng only) + n(PE and Bio only) + n(PE and Eng only) + n(Bio and Eng only) + n(all three) + n(none)

135 = 15 + 30 + 43 + 5 + 10 + 2 + 5 + n(none)

135 = 110 + n(none)

n(none) = 135 - 110

n(none) = 25

b)Number of students that too PE but not Bio

n(PE but not bio)= n(PE only) + n(PE and Eng only)

n(PE but not Bio) = 15 + 10

n(PE but not Bio) = 25

c) Number of students that took ENG but not both BIO and PE

n(ENG but not both BIO and PE) = n(Eng only) + n(Eng and Bio only) + n(Eng and PE only) = 43 + 2 + 10

n(ENG but not both BIO and PE) = 55

d) Number of students that did not take ENG or BIO

n( students that did not take Eng or Bio) = n(PE only) + n(none)

n(students that did not take Eng or Bio) = 15 + 25

n(students that did not take Eng or Bio) = 40

e) Probability that a randomly-chosen student from this group did not take exactly two subjects

n( Students that did not take exactly two subjects) = n(PE only) + n(Bio only) + n(Eng only)

n( Students that did not take exactly two subjects) = 15 + 30 + 43

n( Students that did not take exactly two subjects) = 88

P( Students did not take exactly two subjects) = 88/135

P( Students did not take exactly two subjects) = 0.65

3 0
1 year ago
Read 2 more answers
The original cost of an item is $64, but you have to pay $78.08. What is the markup of the item (as a percent)?
Neko [114]

Answer:

Step-by-step explanation:

The answer is 22 percent.

5 0
2 years ago
A skateboarder starts from rest and maintains a constant forward acceleration of 0.50 meter per second squared for 8.4 s. what i
myrzilka [38]

Answer-

The rider’s displacement during this time is 17.01 m

Solution-

As we know,

s= ut + \frac{1}{2}at^{2}

Where s = displacement,

           u= initial velocity = 0, as the rider starts from rest

           a= acceleration = 0.5 m/s²

           t= time taken = 8.4 s

Putting the values,

s = (0)(8.4) + \frac{1}{2} (0.5)(8.4)^{2} = 17.64 \ m

7 0
2 years ago
Read 2 more answers
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