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2 years ago

What is the domain of the given function? {(3,-2), (6, 1), (-1,4), (5,9), (-4,0)}

Mathematics

1 answer:

grandymaker [24]2 years ago

4 0

Answer:

D = { -4,-1,3,5,6}

Step-by-step explanation:

The domain is the x values or the inputs

D = { 3,6,-1,5,-4}

We normally put them in order from smallest to largest

D = { -4,-1,3,5,6}

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Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?

Debora [2.8K]

Option A

$2x^2(6x-1) + 3(6x-1)$ is one way to determine the factors of $12x^3-2x^2+18x-3$ by grouping

Solution:

Factoring by grouping means that you will group terms with common factors before factoring

Given expression is:

$12x^3-2x^2+18x-3$

Group the first two terms together and then the last two terms together.

$(12x^3-2x^2)+(18x-3)$

We can see that $2x^2$ is common in first two terms

And 3 is common in last two terms

Factor them out

$(12x^3-2x^2)+(18x-3) = 2x^2(6x-1) + 3(6x-1)$

$2x^2(6x-1) + 3(6x-1)$

Thus option A is correct

6 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B12%20%7Bx%7D%5E%7B6%7D%20%20%7By%7D%5E%7B7%7D%20%7D%20%20%5Ctimes%20%20%5C

galina1969 [7]

So, we would need to remember, the one way that me personally would view square rooting would be by simplifying them, and that number would go into that number that many times. So, when doing this kind of problem, we are not truly going to do this, but we are just going to simplify it, and to see what other square "rooter" would go into that.

So, we would need to remember a (key) point, we aren't just multiplying, for the most part, we're simplifying. 

Our result:

$\boxed{\boxed{\bf{2a^2b \sqrt[4]{24a^2b^3} }}}$

We didn't just multiplied it, we also simplified it also.

4 0

2 years ago

When comparing functions, such as Seth’s scenarios for travelling to school, will the function with the greatest initial value c

True [87]

Answer:

It will depend whether is function time dependent or not.

Step-by-step explanation:

If the function is time dependent, the function with greatest initial values continue to be greatest as time increases.

4 0

2 years ago

Read 2 more answers

For each system of equations, drag the true statement about its solution set to the box under the system?

natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

coefficients of x and y are the same and the numerical terms

are the same

- The system of equation has one solution if at least one of the

coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

3 0

2 years ago

A mirror is made of two congruent parallelograms as shown in the diagram. The parallelograms have a combined area of 9 1/3 squar

Vika [28.1K]

Given:
2 parallelograms with an area of 9 1/3 yd²
height of each parallelogram is 1 1/3 yd

Area of parallelogram = base * height

We need to divide the combined area into two to get each parallelogram's base.

9 1/3 = ((9*3)+1)/3 = 28/3

28/3 ÷ 2 = 28/3 * 1/2 = 28/6 yd² or 4 4/6 yd² ⇒ 4 2/3 yd²

Area of each parallelogram is 4 2/3 yd²

4 2/3 yd² = base * 1 1/3 yd

14/3 yd² ÷ 4/3 yd = base

14/3 yd² x 3/4 yd = base
14*3 / 3*4 = base
42 / 12 = base
3 6/12 yd = base
or 3 1/2 yd = base

a) the base of each parallelogram is 3 1/2 yards
b) we can assume that the two parallelograms form a rectangle.
area of a rectangle is length times width.

length is 3 1/2 yds * 2 = 7 yds
width is 3 1/2 yds

Area of rectangle = 7 yds * 3 1/2 yds
Area = 7 yd * 7/2 yd
Area = 7*7 / 2 yd²
Area = 49 / 2 yd²
Area = 24 1/2 yd²

8 0

2 years ago

Read 2 more answers