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2 years ago

The cost of producing x soccer balls in thousands of dollars is represented by h(x) = 5x + 6. The revenue is represented by

Mathematics

2 answers:

Firdavs [7]2 years ago

3 0

Answer:

(k-h)(x) = 4x - 8

Step-by-step explanation:

We know Profit = Revenue - Cost

Basically we gotta subtract cost function from revenue function and get the profit function.

The cost function is h(x) = 5x + 6

The revenue function is k(x) = 9x - 2

Hence, Profit is:

(k-h)(x) = (9x - 2) - (5x + 6)

(k-h)(x) = 9x -2 - 5x - 6

(k-h)(x) = 4x - 8

goldenfox [79]2 years ago

3 0

Answer:

Step-by-step explanation:

The complete question is

The cost of producing x soccer balls in thousands of dollars is represented by h(x) = 5x + 6. The revenue is represented by k(x) = 9x – 2. Which expression represents the profit, (k – h)(x), of producing soccer balls?

A. 14x – 8

B. 14x + 4

C. 4x – 8

D. 4x + 4

The expresison that represents the profit is $(k-h)(x)$ . Which means the profit is the difference between the revenue function and the cost functions, that is

$(k-h)(x)=k(x)-h(x)=9x-2-(5x+6)=9x-2-5x-6=4x-8$

Therefore, the expression that represents profit is 4x-8, whcih is choice C.

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Pachacha [2.7K]

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2 years ago

For any linear function f(x) = mx + b, when does kf(x) = f(kx)?

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2 years ago

In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.

Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

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2 years ago

Read 2 more answers

A large grandfather clock strikes its bell once at 1:00, twice at 2:00, three times at 3:00, etcetera. what is the total number

erastovalidia [21]

There is a formula for adding consecutive integers.
sum = (n * (n+1)) / 2
for summing 1 through 12 it is
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2 years ago

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Lauren has an above-ground pool. To keep the pool's skimmer working well, the water level must be 4 inches from the top of the p

KIM [24]

Answer:

1885.5 m^3 of water

Step-by-step explanation:

I'll assume this is the complete question

Lauren has an above-ground pool. To keep the pool's skimmer working well, the water level must be 4 inches from the top of the pool. When the pool is filled to this recommended level, approximately how many cubic feet of water will it contain? Use π = 3.14

The pool forms a cylinder with a radius of 12 feet and a height of 4.5 feet.

height of pool = 4.5 ft

radius of pool $12^{2}$ = 12 ft

height of water is 4 inches below pool top

12 inches make 1 ft

4 inches = 4/12 ft = 0.33 ft

Therefore, height of water = 4.5 - 0.33 = 4.17 ft

volume of the water in this section of the cylinder will be equal to the volume of the cylinder formed

volume of cylinder formed by the water = volume of water = π $r^{2}$ h

volume = 3.14 x $12^{2}$ x 4.17 = 1885.5 m^3 of water

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2 years ago