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Nana76 [90]
2 years ago
12

The Bakhshali Manuscript shows that another method for calculating nonperfect squares was being used in India by 400 CE. Use thi

s method to find the approximate value of . The nearest perfect square that is less than 22 is , whose square root is . Add the square root from step 1 to to get 4.75. Calculate the quantity one-half times the square of divided by the value found in step 2, or 4.75. Subtract the value found in step 3 from the value found in step 2, or 4.75. The approximate value of is .
Mathematics
2 answers:
vovikov84 [41]2 years ago
7 0
<span>The nearest perfect square that is less than 22 is 16, whose square root is 4. 

</span><span>Add the square root from step 1 to 3/4 to get 4.75.

</span>Calculate the quantity one-half times the square of  divided by the value found in step 2, or 4.75. (1/2  * (3/4)^2) <span>÷ 4.75 = 0.06.
</span>
Subtract the value found in step 3 from the value found in step 2, or 4.75.
The approximate value of <span>√22 is 4.69.</span>
sleet_krkn [62]2 years ago
4 0

Answer:

1.  22

2. 4 

3. 0.06.

4.  4.69.

Read more on Brainly.com - brainly.com/question/7481589#readmore

Step-by-step explanation:

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If the odds of catching the flu among individuals who take vitamin C is 0.0342 and the odds of catching the flu among individual
melamori03 [73]

Answer:

Correct option (A).

Step-by-step explanation:

The probability of an individual catching a flu when he or she has taken vitamin C is, P (F|C) = 0.0342.

The probability of an individual catching a flu when he or she has not taken vitamin C is, P (F|C') = 0.2653.

Th ratio of individuals who caught the flu when they did not take vitamin C to those who took vitamin C is:

=\frac{P(F|C')}{P(F|C)}\\ =\frac{0.2653}{0.0342} \\=7.7573

This implies that:

P(F|C')=7.7573\times P(F|C)

Thus, the the individuals not taking vitamin C are 7.7573. Times more likely to catch the flu than individuals taking vitamin C.

The statement is True.

4 0
2 years ago
Enlarge the triangle by scale factor 0.5 using 3,1 as the centre of enlargement
NISA [10]

Answer:

the points are :

(0,-1)

(0,0)

(-1,3)

(If you are using MathsWatch) For this question the triangle gets smaller so i'm not sure why it says Enlarge the triangle.

6 0
1 year ago
The system of equations
cupoosta [38]

Answer:

z = -12

Step-by-step explanation:

The given system of equations is:

xy/(x + y) = 1 ...........................(1)

xz/(x + z) = 2...........................(2)

yz/(y + z) = 3...........................(3)

From (1): x + y = xy

=> y = xy - x

y = x(y - 1)

x = y/(y - 1).......................................(4)

From (2): 2(x + z) = xz

=> 2x + 2z = xz

2x = xz - 2z

2x = z(x - 2)

z = 2x/(x - 2) ....................................(5)

From (3): 3(y + z) = yz

=> 3y + 3z = yz

3y = yz - 3z

3y = z(y - 3)

z = 3y/(y - 3)....................................(6)

Comparing (5) and (6)

2x/(x - 2) = 3y/(y - 3)

2x(y - 3) = 3y(x - 2)

2xy - 6x = 3xy - 6y

6(y - x) = xy .................................(7)

But from (1): xy = x + y

Using this in (7), we have

6(y - x) = x + y

6y - y - 6x - x = 0

5y - 7x = 0

5y = 7x

x = 5y/7................................................(8)

Using this in (4)

5y/7 = y/(y - 1)

1/(y - 1) = 5/7

(y - 1) = 7/5

y = 1 + 7/5

y = 12/5..........................................(9)

Using this in (8)

x = 5(12/5)/7 = 12/7 .......................(10)

Using (10) in (5)

z = 2x/(x - 2)

z = 2(12/7) ÷ (12/7 - 2)

= 24/7 ÷ -2/7

= 24/7 × (-7/2)

= -24/2 = -12

z = -12.

4 0
2 years ago
N a circle with a radius of 2.8 cm, an arc is intercepted by a central angle of π5 radians. what is the arc length? use 3.14 for
Vilka [71]
By definition, the arc length is given by:
 arc = (theta) * (R)
 Where,
 theta: central angle
 R: radius
 Substituting values we have:
 arc = (π / 5) * (2.8)
 Rewriting we have:
 arc = ((3.14) / 5) * (2.8)
 arc = 1.7584 cm
 Round to the hundredth:
 arc = 1.76 cm
 Answer:
 
the arc length is:
 
arc = 1.76 cm
8 0
2 years ago
Read 2 more answers
Given two vectors a⃗ =4.00i^+7.00j^ and b⃗ =5.00i^−2.00j^ , find the vector product a⃗ ×b⃗ (expressed in unit vectors). what is
FinnZ [79.3K]

The vector product of \boxed{a \times b =  - 43\hat k} and the magnitude of a \times b is \boxed{43}.

Further explanation:

Given:

Vector a is \vec a = 4.00\hat i + 7.00\hat j.

Vector b is \vec b = 5.00\hat i - 2.00\hat j.

Explanation:

The cross product of a \times b can be obtained as follows,

\begin{aligned}a \times b &= \left| {\begin{array}{*{20}{c}}{\hat i}&{\hat j}&{\hat k} \\4&7&0\\5&{ - 2}&0 \end{array}}\right|\\&= \hat i\left( {0 - 0} \right) - \hat j\left( {0 - 0} \right) + \hat k\left( { - 9 - 35} \right)\\&= 0\hat i - 0\hat j - 43\hat k\\&= - 43\hat k\\\end{aligned}

The vector can be expressed as follows,

a \times b =  - 43\hat k

The magnitude of a \times bcan be obtained as follows,

\begin{aligned}\left| {a \times b} \right| &= \sqrt {{0^2} + {0^2} + {{\left( { - 43} \right)}^2}}\\&= \sqrt {{{43}^2}}\\&= 43\\\end{aligned}43404

The vector product of \boxed{a \times b =  - 43\hat k} and the magnitude of a \times b is \boxed{43}.

Learn more:

  1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Vectors

Keywords: two vectors, vector product, expressed in unit vectors, magnitude, vector a, vector b, a=4.00i^+7.00j^, b=5.00i^-2.00j^, unit vectors, vector space.

8 0
2 years ago
Read 2 more answers
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