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uranmaximum [27]
2 years ago
12

The number of hours a group of contestants spends preparing for a quiz show is listed below. What is the frequency table that re

presents that data?
8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
Mathematics
1 answer:
harkovskaia [24]2 years ago
8 0
I'll just show you how to make a frequency table using the above data. 
We will group the data into class intervals and determine the frequency of the group.

<span>8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
</span>
smallest data value = 4
highest data value = 99
difference = 99 - 4 = 95
number of data = 17

Let us assign a class interval of 20.

Class Interval     Tally                              Frequency
0-20                    8, 12, 4, 18, 9,                     5
21-40                25, 32, 39, 36, 33                 5 
41-60                45, 50, 67                              3
61-80                62, 73, 80                              3
81-100              99                                           1

That is how a frequency table look like. Usually, under the Tally column, tick marks are written instead of the numbers but for easier monitoring, I used the numbers in the data set.
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Write an equation for the 4th degree polynomial graphed below. Use k if your leading coefficient is positive and −k if your lead
Afina-wow [57]
Ho ho ho, lets get this party started
ok so I'm just really excited to use this stuff that I just learned

so

multiplicites
if a root or zero has an even multilicity, the graph bounces on that root
if the root or zero has an odd multiplicty, the graph goes through that root

so
roots are
-1
2
4
multiplicty is how many times it repeats
2 has even multiplity
we just do 2 is odd and 1 is even so
for roots, r1 and r2, the facotrs would be
(x-r1)(x-r2)
so
(x-(-1))^1(x-2)^2(x-4)
(x+1)(x-2)^2(x-4)
this is a 4th degre equaton
normally, it is goig from top right to top left
it is upside down
theefor it has negative leading coefient



y=-k(x+1)(x-4)(x-2)^2
8 0
2 years ago
Read 2 more answers
The function f(t) = 4t2 − 8t + 8 shows the height from the ground f(t), in meters, of a roller coaster car at different times t.
lidiya [134]

Answer:

f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 4 meters from the ground

Step-by-step explanation:

The function is a quadratic where t is time and f(t) is the height from the ground in meters. You can write the function f(t) = 4t2 − 8t + 8 in vertex form by completing the square. Complete the square by removing a GCF from 4t2 - 8t. Take the middle term and divide it in two. Add its square. Remember to subtract the square as well to maintain equality.

f(t) = 4t2 − 8t + 8

f(t) = 4(t2 - 2t) + 8                                  The middle term is -2t

f(t) = 4(t2 - 2t + 1) + 8 - 4                        -2t/2 = -1; -1^2 = 1

f(t) = 4(t-1)^2 + 4                                      Add 1 and subtract 4 since 4*1 = 4.

The vertex (1,4) means at a minimum the roller coaster is 4 meters from the ground.

  • f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 2 meters from the ground
  • f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 4 meters from the ground
  • f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 1 meter from the ground
  • f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 4 meters from the ground
8 0
2 years ago
Read 2 more answers
When two pipes fill a pool together, they can finish in 5 hours. If one of the pipes fills half the pool then the other takes ov
Alexxandr [17]

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷The answer is 18 hours.

Explanation: If you look carefully, you can see that the answer is the second condition as well. If one pipe did half, then the other pipe took over and that took 18 hours, that means that it equals one pipe filling the pool continuously by itself. :)

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

DOGE

3 0
2 years ago
For the given position vectors r(t) compute the unit tangent vector T(t) for the given value of t .
algol13

Answer:

a) T(t) = \frac{}{5}=

T(4) =

b) T(t) = \frac{}{8\sqrt{37}}

T(4) =

c) T(t) = \frac{}{2425825977}

T(4) = \frac{1}{2425825977}

Step-by-step explanation:

The tangent vector is defined as:

T(t) = \frac{r'(t)}{|r'(t)|}

Part a

For this case we have the following function given:

r(t) =

The derivate is given by:

r'(t) =

The magnitude for the derivate is given by:

|r'(t)| = \sqrt{25 sin^2(5t) +25 cos^2 (5t)}= 5\sqrt{cos^2 (5t) + sin^2 (5t)} =5

And then the tangent vector for this case would be:

T(t) = \frac{}{5}=

And for the case when t=4 we got:

T(4) =

Part b

For this case we have the following function given:

r(t) =

The derivate is given by:

r'(t) =

The magnitude for the derivate is given by:

|r'(t)| = \sqrt{4t^2 +9t^4}= t\sqrt{4 + 9t^2}

|r'(4)| = \sqrt{4(4)^2 +9(4)^4}= 4\sqrt{4 + 9(4)^2} = 4\sqrt{148}= 8\sqrt{37}

And then the tangent vector for this case would be:

T(t) = \frac{}{8\sqrt{37}}

And for the case when t=4 we got:

T(4) =

Part c

For this case we have the following function given:

r(t) =

The derivate is given by:

r'(t) =

The magnitude for the derivate is given by:

|r'(t)| = \sqrt{25e^{10t} +16e^{-8t} +1}

|r'(t)| = \sqrt{25e^{10*4} +16e^{-8*4} +1} =2425825977

And then the tangent vector for this case would be:

T(t) = \frac{}{2425825977}

And for the case when t=4 we got:

T(4) = \frac{1}{2425825977}

5 0
2 years ago
Jada and lin are comparing inches and feet. Jada says that the constant of proportionality is 12. Lin says it is 1/2.
Inga [223]

Jada and lin are comparing inches and feet.

Let I denote inches and F denote feet.

It is given that

 I =k F or F=m I

So, I/F=k or m=F/I

As  we know 1 feet = 12 inches

constant  of proportionality i.e k=1/12

In case 2, constant of proportionality=12/1=12

So, Jada must have calculated ratio of feet to inches while Lin has calculated the ratio of inches to feet.

5 0
2 years ago
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