Answer:
the probability that the exceeded 65 = 0.3707
The average score of the 36 golfers exceeded 65
= 36 X 0.3707 = 13.3452
Step-by-step explanation:
<u>Step 1</u>:-
The average score of all golfers for a particular course has a mean of 64 and a standard deviation of 3.
mean (μ) = 64
standard deviation (σ) =3
by using normal distribution
given (μ) = 64 and (σ) =3
i) when x =65

P( X≥ 65) = P(z≥0.33)
= 0.5 - A(z₁)
= 0.5 - 0.1293 (see normal table)
= 0.3707
The average score of the 36 golfers exceeded 65
= 36 X 0.3707 = 13.3452
Answer:
Subtract 11 from both sides
Step-by-step explanation:
Answer:
0.24315
Step-by-step explanation:
Using the z score formula to solve this question
z = (x - μ) / σ,
Such that:
x = raw score
μ = population mean
σ = population standard deviation.
From the question:
x = 3000
μ = 3550
σ = 870
z = (3000 - 3550) / 870
z = -550/870
z = -0.6962
Using the z score table as well as probability calculator(as requested in the question to find the z score)
The probability of having less than 3000 is obtained as:
P(x<3000) = 0.24315
Answer:
The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.
Step-by-step explanation:
Solution
Normally, a distribution sample is mostly affected by sample size.
As a rule, sampling error decreases by half by increasing the sample size four times.
In this case, B sample is 2 times higher the A sample size.
Now, the Mean sampling error is affected and is not higher for A.
But it's sample is huge for this, Thus, they are almost equal
Variability of simulation decreases with increase in number of trials. A has less variability.
With increase number of trials, variability of simulation decreases, so A has less variability.
Answer:
1. Car B is moving east at 70MPh and is in from of car A
2.car B is moving west at 70 mph and is behind car A
Step-by-step explanation:
Use the cardinal point system to evaluate the problem first