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Tju [1.3M]
2 years ago
5

Ellie buys a mobile phone in spain for €352.50. Her brother jack buys an identical phone from japan for ¥39856. Using exchange r

ates £1 = €1.41, £1 = ¥188. Which country is the mobile phone cheaper

Mathematics
2 answers:
Nonamiya [84]2 years ago
8 0

Answer:

The answer to your question is: Japan

Step-by-step explanation:

Mobile cost in Spain = € 352.5

Mobile cost in Japan = ¥39856

Exchange rate = £1 = €1.41

                           £1 = ¥188

Cost of mobile in pounds

                       £ 1 ------------------ € 1.41

                        x  -----------------   €352.5

                       x = (352.5 x 1) / 1.41

                       x= £250

                      £1   ------------------  ¥188

                      x    ----------------- -¥ 39856

                     x = (39856 x 1) / 188

                     x = £212

Then, it was cheaper in Japan

Vadim26 [7]2 years ago
5 0

Answer:

Step-by-step explanation:

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Answer: 985 g

Step-by-step explanation:

Total mass = 8 × 500g = 4000g

Let the three new packs be X, Y, and Z, for first, second, and third pack respectively.

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let's put X and Z in terms of Y, since we're trying to solve for the second pack.

X = 2Y, and Z = Y + 60

Therefore,

4000 = X + Y + Z

4000 = 2Y + Y +Y + 60

4000 = 4Y +60

4000 - 60 = 4Y

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3940 ÷ 4 = Y

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2 years ago
How do you solve this? Please help me (i will give you 14 points)
azamat

Answer:

X can be 2,3,4,5,6,7,8

Step-by-step explanation:

X is greater than or equal  to 2  and less than or equal to 8

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Uranus has a mass of 8.68 1025 kg and a radius of 2.56 107 m. Assume it is a uniform solid sphere. The distance of Uranus from t
Lelechka [254]

Answer

Given,

Mass of the Uranus, M = 8.68 x 10²⁵ Kg

Radius of Uranus, R = 2.56 x 10⁷ m

Distance of Uranus, D = 2.87 x 10¹² days

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moment of inertia of the Uranus

  I = \dfrac{2}{5}MR^2

  I = \dfrac{2}{5}\times 8.68\times 10^{25}\times (2.56\times 10^7)^2

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  Angular speed

     \omega = \dfrac{2\pi}{T} = \dfrac{2\pi}{17.3\times 3600}\

    \omega = 1 \times 10^{-4}

 Rotational Kinetic energy

     KE = \dfrac{1}{2}I\omega^2

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b) Rotational Kinetic energy of Uranus in its orbit around sun

moment of inertia of the Uranus

  I = \dfrac{2}{5}MR^2+ Ma^2

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      I = 7.15 x 10⁵⁰ kg.m²

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     \omega = \dfrac{2\pi}{T} = \dfrac{2\pi}{3.08\times 10^4\times 3600\times 24}\

    \omega =2.36\times 10^{-9}

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     KE = \dfrac{1}{2}I\omega^2

     KE = \dfrac{1}{2}\times 7.15\times 10^{50}\times (2.36\times 10^{-9})^2

      KE = 1.99\times 10^{33}\ J

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