I'm pretty sure the answer will be 6/10
Hope this helps, best of luck, terribly sorry if I'm wrong if I am my apologies
~Animaljamissofab ♥
Case 1: If we multiply f(x) = |x| by a fraction greater than zero and less than 1, the width of the resulting graph will increase. If the vertex of the original function is moved 2 units to the right, then we'd replace |x| with |x-2| Only the coefficient (3/4) satisfies the "wider graph" requirement here.
Next time you list answr possibilities, please type them in only one per line, or separate them with commons, semicolons or the like.
Answer:
AC and OA
Step-by-step explanation:
-A secant is a line connecting two points on the circle.
-Given the square OABC of sides 6cm and a circle of r=5cm and the center of the circle as O, and that the radius of the circle is less than the side of the square:
-The circle passes through OA and OC, but doesn't pass through AB and BC.
Hence, AC and OA are the circle's secants.
To solve the quadratic equation given by 0=x^2-9x-20, we use the quadratic formula given by:
x=[-b+\- sqrt(b^2-4ac)]/(2a)
where,
a=1,b=-9,c=-20
thus substituting the above values into our formula we get:
x=[9+\-sqrt(9^2-4(-20*1))/(2*1)
x=[9+\-sqrt(161)]/2
x=[9+sqrt161]/2 or x=[9-sqrt161]/2
Use the fact that 
to solve it.
