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mojhsa [17]
2 years ago
15

John should drive to his workplace and back to home. On the way to the workplace it was raining, so he drove at speed of 42mph.

On the way back the rain was over so his speed was 54mph. What was John's average speed, for the whole trip?
Pls help im not good with these problems Q_Q
Mathematics
1 answer:
elixir [45]2 years ago
5 0

Answer:

47.25 mph

Step-by-step explanation:

Represent the total distance traveled as 2x. Average speed= total distance/total time

When going at 42 mph, the time would be x/42 and when going at 54 mph the time would be x/54 to travel x distance. Add x/42 and x/54 together to get 16x/378. Then divide 2x by 16x/378 to get 47.25 mph. Also this is RSM innit?

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Which equation shows the inverse property of multiplication?
Pavel [41]
The correct answer is C.

The inverse property of multiplication states that a number multiplied by its reciprocal equals 1. The reciprocal of 1/2 is 2/1, or 2.
4 0
2 years ago
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Rebeckah answered 42 of the 60 questions correctly on a test. Which method should she use to find the percent of questions she a
Nataly_w [17]

Answer:

D.

Step-by-step explanation:

42/60=70% so the only option that also equals 70% is letter D.

3 0
1 year ago
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Farmer John walks his pet pig around his barn every day. The barn is 25
kkurt [141]

Answer:

900m

Step-by-step explanation:

A=wl

W=25

L=12

A=25 x 12

A= 300

300 meters x 3 laps = 900 meters walked

4 0
2 years ago
An elliptical culvert is 3.5 feet tall and 6 feet wide. It is filled with water to a depth of 0.95 feet. Find the width of the s
maks197457 [2]

Answer:

W_s \approx5.3

Step-by-step explanation:

From the question we are told that

Height H=3.5ft

Weight W= 6ft

Depth  D=0.95ft

Generally the equation for ellipses is given as

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

Where

b=H/2\\b=3.5/2\\Therefore\\b=1.75\\a=W/2\\a=6/2\\Therefore\\a=3\\

\frac{x^2}{3^2} +\frac{y^2}{1.75^2} =1

Generally to find y in the equation \frac{x^2}{a^2} +\frac{y^2}{b^2} =1

y=-b+d

y=-1.75+0.95

y=-0.8

Therefore

\frac{x^2}{3^2} +\frac{(0.8)^2}{1.75^2} =1

\frac{x^2}{3^2} =1-\frac{(0.8)^2}{1.75^2}

\frac{x^2}{3^2} =1-0.2089795918

X^2 =3^2(1-0.2089795918)

X^2 =7.119183674

X =\sqrt{7.119183674}

X =2.66817984

Therefore the width of the given stream is

W_s=2.66817984*2

W_s=5.33635968

W_s \approx5.3

3 0
2 years ago
Every day, there are 3 times more likes on an internet video of a cat which is modeled by the function c(n) = (3)n − 1, where n
Kisachek [45]

Answer: Hi! the answer is D, now let's prove it:

Ok, let's analyze our problem; we know two facts:

1) the first day, the video has 143 likes

2) each day that pases, there are 3 times more likes.

this means, that the day 1, the video has 143 like, the day 2, has 3*143 = 429 likes, the day 3, it has 3*429 = 1287

now, this is f(n) = the number 143 multiplied by 3 (n - 1) times, where n is the amount of days.

the function that describes this is f(n) = 143*3^{n -1}

when n = 1, f(1) = 143*3^{0} = 143

when n = 2, f(2) =  143*3^{1} = 143*3

and so on, so the correct answer is D.

Also you can check the other functions if you like:

A) c(1) = (3)(143)^{1-1} = 3, so A doesn't work for the first day.

B) c(1) = 143^{1-1} = 1, B neither works for the first day.

C)  c(1) = (3)143 − 1 = 428. C neither works for the first day

6 0
2 years ago
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