Answer: ∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE are the additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS.
Step-by-step explanation:
Given: ΔXYZ and ΔEFG such that ∠X=∠F
To prove they are congruent by using ASA or AAS conruency criteria
we need only one angle and side.
1. ∠Z ≅ ∠G(angle) and XZ ≅ FG(side)
so we can apply ASA such that ΔXYZ ≅ ΔFEG.
2. ∠Z ≅ ∠G (angle)and ∠Y ≅ ∠E (angle), we need one side which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
3. XZ ≅ FG (side) and ZY ≅ GE (side), we need one angle which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
4. XY ≅ EF(side) and ZY ≅ FG(side), not possible.
5. ∠Z ≅ ∠G(angle) and XY ≅ FE(side),so we can apply ASA such that
ΔXYZ ≅ ΔFEG.
Answer:
The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
88% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)
Answer:
−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3
Step-by-step explanation:
(p2qr+pq2r+pqr2)((−p)(q)+qr+−pr)
(p2qr)((−p)(q))+(p2qr)(qr)+(p2qr)(−pr)+(pq2r)((−p)(q))+(pq2r)(qr)+(pq2r)(−pr)+(pqr2)((−p)(q))+(pqr2)(qr)+(pqr2)(−pr)
−p3q2r+p2q2r2−p3qr2−p2q3r+pq3r2−p2q2r2−p2q2r2+pq2r3−p2qr3
−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3
Answer:
Step-by-step explanation:
All those words! Just use math.
