14C3 = 14! / 11!3!
<span>= 14 x13 x12 / 3x2x1 </span>
<span>= 2184 / 6 </span>
<span>= 364 different combinations </span>
<span>The first movie can be any of 14 </span>
<span>As you have already seen one the second movie can be any of the 13 remaining </span>
<span>As you have already seen two the third movie can be any of the 12 remaining. </span>
<span>Therefore there are 14 x 13 x 12 = 2184 PERMUTATIONS of movies you can see. </span>
<span>However among those 2184 different permutations will be instances where you have watched the same three movies but just in a different order. </span>
<span>eg ET, The Piano, Harry Potter = ET Harry Potter The Piano = The Piano, ET, Harry Potter = The Piano Harry Potter ET = Harry Potter ET The Piano = Harry Potter The Piano ET. </span>
<span>For each set of three films there are 3! or 3x2x1 or SIX different ways they can be arranged in. </span>
<span>Therefore we need to DIVIDE the above 2184 permutations by 6 to get the number of COMBINATIONS of different films that can be watched. </span>
<span>2184 / 6 = 364</span>
Since there are 6 students out of which one needs to be selected, the principal chose two die on which there are six numbers each numbered from 1 , 2, 3, 4, 5, 6.
Since there are two dice, the total possible outcome is 36.
Hence, the probability of getting one number each is 1/36
Hence, the principal used a fair method because each result is an equally likely possible outcome.
Option B is correct.
Answer:
The factors of x^2+3x-4 are (x-1)(x+4) ....
Step-by-step explanation:
We have to find the factors of x^2+3x-4
As we know that this is a quadratic equation.
So we have to find the roots first.
The roots are -1 and 4.
Now completing the quadratic formula using the roots we have :
x^2+4x-x-4
Make a pair of first two terms and last two terms:
(x^2+4x)-(x+4)
Now take out the common from each pair:
x(x+4)-1(x+4)
(x-1)(x+4)
Thus the factors of x^2+3x-4 are (x-1)(x+4) ....
