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e-lub [12.9K]
2 years ago
11

Every day, there are 3 times more likes on an internet video of a cat which is modeled by the function c(n) = (3)n − 1, where n

is the number of days since the video posted. On the first day, there were 143 likes. What is the function that shows the number of likes each day?
A. c(n) = (3)(143)^{n-1}
B. c(n) = 143^{n-1}
C. c(n) = (3)143 − n
D.143(3)^{n-1}
Mathematics
1 answer:
Kisachek [45]2 years ago
6 0

Answer: Hi! the answer is D, now let's prove it:

Ok, let's analyze our problem; we know two facts:

1) the first day, the video has 143 likes

2) each day that pases, there are 3 times more likes.

this means, that the day 1, the video has 143 like, the day 2, has 3*143 = 429 likes, the day 3, it has 3*429 = 1287

now, this is f(n) = the number 143 multiplied by 3 (n - 1) times, where n is the amount of days.

the function that describes this is f(n) = 143*3^{n -1}

when n = 1, f(1) = 143*3^{0} = 143

when n = 2, f(2) =  143*3^{1} = 143*3

and so on, so the correct answer is D.

Also you can check the other functions if you like:

A) c(1) = (3)(143)^{1-1} = 3, so A doesn't work for the first day.

B) c(1) = 143^{1-1} = 1, B neither works for the first day.

C)  c(1) = (3)143 − 1 = 428. C neither works for the first day

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Answer:

a) W(t) = 371(1.168)^{t}

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Step-by-step explanation:

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W(t) = W(0)(1+r)^{t}

W(t) = 371(1+0.168)^{t}

W(t) = 371(1.168)^{t}

(b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?

This is t years after the end of 2014, in which t found when W(t) = 600. So

W(t) = 371(1.168)^{t}

600 = 371(1.168)^{t}

(1.168)^{t} = \frac{600}{371}

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\log{a^{t}} = t\log{a}

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\log{(1.168)^{t}} = \log{1.61725}

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