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vazorg [7]
2 years ago
8

Suppose the population of a town is 15,200 and is growing 2% each year. Write an equation to model the population growth. Predic

t the population after 10 years. y = 15,200 ∙ 2x; about 15,564,800 people y = 2 ∙ 15,200x; about 304,000 people y = 15,200 ∙ 1.02x; about 18,529 people y = 15,200 ∙ 2x; about 18,529 people
Mathematics
1 answer:
larisa [96]2 years ago
5 0
For this case, what you need to know is that to model this problem, you must use equations of the potential type:
 y = A * (b) ^ t
 Where:
 A: initial population.
 b: growth rate.
 t: time.
 Substituting values we have:
 y = 15200 * (1.02) ^ t
 After 10 years we have:
 y = 15200 * (1.02) ^ 10
 y = 18529
 Answer:
 An equation to model of the population growth is:
 y = 15,200 ∙ 1.02 ^ x
 the population after 10 years is:
 about 18,529
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Answer:

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Step-by-step explanation:

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Where Vo is the inicial value of the car, r is the depreciation rate and t is the amount of years.

We have that Vo = 25000, r = -18.5% = -0.185, so:

V(t) = 25000 * (1-0.185)^t

V(t) = 25000 * (0.815)^t

In year 3, we have:

V(3) = 25000 * (0.815)^3 = 13533.58

In year 4, we have:

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The depreciation from year 3 to year 4 was:

V(3) - V(4) = 13533.58 - 11029.87 = $2503.71

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2 years ago
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andreev551 [17]

Answer:

From $1600 to $3400.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

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Therefore, the defense has a probability of 22% of score that goal.

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Answer:

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