We can start solving this problem by first identifying what the elements of the sets really are.
R is composed of real numbers. This means that all numbers, whether rational or not, are included in this set.
Z is composed of integers. Integers include all negative and positive numbers as well as zero (it is essentially a set of whole numbers as well as their negated values).
W on the other hand has 0,1,2, and onward as its elements. These numbers are known as whole numbers.
W ⊂ Z: TRUE. As mentioned earlier, Z includes all whole numbers thus W is a subset of it.
R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.
0 ∈ Z: TRUE. Zero is indeed an integer thus it is an element of Z.
∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are <u>not</u> an element of R).
{0,1,2,...} ⊆ W: TRUE. The set on the left is exactly what is defined on the problem statement for W. (The bar below the subset symbol just means that the subset is not strict, therefore the set on the left can be <u>equal</u> to the set on the right. Without it, the statement would be false since a strict subset requires that the two sets should not be equal).
-2 ∈ W: FALSE. W is just composed of whole numbers and not of its negated counterparts.
Answer: see the graphic
Step-by-step explanation:
A. Type I error helps us to conclude that the flight is not profitable, when in fact it is profitable.
B. a = 0.05
C. Type II error does not show that the flight is profitable
Answer:
atleast 52
Step-by-step explanation:
Given that an employment agency requires applicants average at least 70% on a battery of four job skills tests.
An applicant scored 70%, 77%, and 81% on the first three exams,
Since weightages are not given we can assume all exams have equal weights
Let x be the score on the 4th test
Then total of all 4 exams = 
Average should exceed 70%
i.e.
Comparing the two totals we have
Hemust score on the fourth test a score atleast 52 to maintain a 70% or better average.
Answer: P’ (5,10) , Q’ (-5,10) , R’ ( 0,-15)
Step-by-step explanation:
Just multiply 2.5 by the x,y
10? Im not sure though my friend just told me it was 10
