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1 year ago

What is the value of k in the equation below? 5k - 2k = 12? 1 1/5, 1 5/7, 3, 4

2 answers:

8 0

Hi there!

5k - 2k = 12
Solve for K
3k = 12
Divide both sides by 3
3k/3 = 12/3
k = 4
The correct answer is : 4

I hope that helps!
Brainliest answer :)

kondaur [170]1 year ago

3 0

Answer:4

Step-by-step explanation:

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At smith’s Mountain Lake Boat Rentals, it cost $25 per hour to rent a pontoon boat, plus a one-time

sergey [27]

Answer:

Jones family paid a total of $139

Step-by-step explanation:

Smith's Mountain Lake Boat provides Rental services that can be expressed as follows;

Total cost=cost per hour×number of hours rented+one time cleaning deal

For Benael's family;

Benael family total cost=Cost per hour×number of hours rented+one-time cleaning deal

where;

Benael family total cost=$226.50

Cost per hour=$25

Number of hours rented=11 am-6:30 pm=7 hours 30 minutes=7.5 hours

One time cleaning deal=x

Replacing;

226.50=(25×7.5)+x

187.5+x=226.50

x=226.50-187.5

x=39

One time cleaning deal=$39

For Jones family;

Jones family total cost=Cost per hour×number of hours rented+one-time cleaning deal

where;

Cost per hour=$25

Number of hours rented=9 am-1 pm=4 hours

One time cleaning deal=$39

Replacing;

Jones family total cost=(25×4)+39

Jones family total cost=$139

Jones family paid a total of $139

4 0

2 years ago

The angle measures associated with which set of ordered pairs share the same reference angle

Trava [24]

Answer:

Option 3 is right.

Step-by-step explanation:

Reference angle of x is obtained by either 180-x, 180+x. or 360-x depending on the posiiton of terminal whether II quadrant or iv quadrant, or iii quadrant, etc.

In whatever way we find reference angles,

cos will remain cos only and sin will remain sin only there may be only changes in sign.

Of all the ordered pairs given, we find that I, II, and Iv there is a switch over form cos to sine and sin to cos. Hence these options cannot be for reference angles.

III option is $(-\frac{1}{2} ,\frac{-\sqrt{3} }{2} )(\frac{1}{2} ,\frac{\sqrt{3} }{2} )$

show that both sign and cos changed sign. This is possible only in III quadrant.

ie reference angle of orignal angle t = 180+t

SO this option is right.

7 0

1 year ago

Read 2 more answers

Quadrilateral A’B’C’D’ is a dilation of quadrilateral ABCD about point P. Quadrilateral ABCD is shown. Side AB is labeled 5. Sid

Stolb23 [73]

Answer: The correct option is (A) reduction.

Step-by-step explanation: Given that the quadrilateral A'B'C'D' is a dilation of the quadrilateral ABCD.

As shown in the given figure, the lengths of the sides of quadrilateral ABCD are as follows:

AB = 5 units, BC = 4 units, CD = 10 units and DA = 6 units.

And, the lengths of the sides of quadrilateral A'B'C'D' are as follows:

$A'B'=1\dfrac{1}{4}=\dfrac{5}{4}~\textup{units},~~B'C'=1~\textup{units},~~C'D'=2\dfrac{1}{2}=\dfrac{5}{2}~\textup{units},\\\\D'A'=1\dfrac{1}{2}=\dfrac{3}{2}~\textup{units}.$

We know that the dilation will be an enlargement if the scale factor is greater than 1 and it will be a reduction if the scale factor is less than 1.

Now, the scale factor is given by

$S=\dfrac{\textup{length of a side of the dilated figure}}{\textup{length of the corresponding side of the original figure}}\\\\\\\Rightarrow S=\dfrac{A'B'}{AB}=\dfrac{\frac{5}{4}}{5}=\dfrac{5}{4\times5}=\dfrac{1}{4}$