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1 year ago

Triangle A and triangle B are drawn on the grid. Describe fully the single transformation which maps triangle A onto triangle B.

Mathematics

1 answer:

madam [21]1 year ago

7 0

Answer:

Step-by-step explanation:

Triangle A, transforms into a smaler size, and goes into full shape. Triangle B, goes into the negative numbers.

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Estimate <br> 72 x 362 / 0.49

andrew11 [14]

53191.8367347

thx for the points

3 0

1 year ago

Read 2 more answers

4. Fatore as expressões. a) 4x4y2 –6x3y3 +8x2y4 = b) 18ab3c² +27a3b4c3 -9a2b5c4 -45a2b3c2 = c) a2+3ab-2ac-6bc= d) x3–3x2y2 +6y3

erastovalidia [21]

Answer:

don't ask many questions at 1time

7 0

2 years ago

25 POINTS

uysha [10]

Answer:

a reflection over the x-axis and then a 90 degree clockwise rotation about the origin

Step-by-step explanation:

Lets suppose triangle JKL has the vertices on the points as follows:

J: (-1,0)

K: (0,0)

L: (0,1)

This gives us a triangle in the second quadrant with the 90 degrees corner on the origin. It says that this is then transformed by performing a 90 degree clockwise rotation about the origin and then a reflection over the y-axis. If we rotate it 90 degrees clockwise we end up with:

J: (0,1) , K: (0,0), L: (1,0)

Then we reflect it across the y-axis and get:

J: (0,1), K:(0,0), L: (-1,0)

Now we go through each answer and look for the one that ends up in the second quadrant;

If we do a reflection over the y-axis and then a 90 degree clockwise rotation about the origin we end up in the fourth quadrant.

If we do a reflection over the x-axis and then a 90 degree counterclockwise rotation about the origin we also end up in the fourth quadrant.

If we do a reflection over the x-axis and then a reflection over the y-axis we also end up in the fourth quadrant.

The third answer is the only one that yields a transformation which leads back to the original position.

4 0

1 year ago

Read 2 more answers

Jack and jill exercise in a 25.0-m-long swimming pool. jack swims nine lengths of the pool in 2 minutes and 34.5 seconds, while

grin007 [14]

Jack swims a distance of 9*25.0m=225.0 meters is 2 min and 34.5 seconds.

2 min and 34.5 seconds are 2*60sec +34.5 sec= 154.5 s

Jill covers 10*25.0m = 250 m in 154.5 s.

$\displaystyle{ Average\ Speed= \frac{Distance\ traveled}{Time \ of \ travel}\\\\$

$\displaystyle{ Average \ Velocity = \frac{Displacement}{time}$

thus,

the speed of Jack is : 225.0 meters /154.5 s =(225/154.5) m/s = 1.46 m/s

the speed of Jill is : 250.0 meters /154.5 s =(250/154.5) m/s = 1.62 m/s

Assuming Jack and Jill depart from point 0 towards the positive direction,

each even number of lengths, means Displacement = 0, and each odd number of lengths means Displacement = 25 m

So, average Velocity of Jill is 0,

average velocity of Jack is 25/ 154.5 = 0.16 m/s

Answer:

Average Speed of Jack : 1.46 m/s

Average Speed of Jill : 1.62 m/s

Average Velocity of Jack : 0

Average Velocity of Jill : 0.16 m/s

5 0

2 years ago

In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the

Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

$(AB)^2=(BC)^2+(AC)^2$