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spin [16.1K]
2 years ago
14

If the manager at first city bank surveys a sample of 100 customers to determine how many miles they live from the​ bank, is the

mean travel distance for this sample considered a parameter or a​ statistic? explain.
Mathematics
1 answer:
padilas [110]2 years ago
3 0
The answer to this question would be  yes, they are parameter.

Parameter is a data that can show the tendency of the sample. The example would be mean, mode, median. The parameter can be used to show how much similarity or differences between two sample. 
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time should be placed on the independent/y-axis

parking fee should be placed on the dependent/x-axis

Step-by-step explanation:

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If Adam orders a book from Store X, how much will he owe to the nearest cent? The tax rate only applies to the cost of
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B) $19.72

Step-by-step explanation:

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Function Representations
viktelen [127]

Answer:

See joint picture.

Step-by-step explanation:

The study lasts 6 days. Since the amount of plant food decreased an equal amount each day, and since the whole 72 millimeters were used, it means that plants consumed 72/6 = 12 millimeters daily.

All the results given come from this justification.

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2 years ago
Which quadratic equation is equivalent to (x2 – 1)2 – 11(x2 – 1) + 24 = 0? u2 – 11u + 24 = 0 where u = (x2 – 1) (u2)2 – 11(u2) +
Vinvika [58]
<span><span>u2</span> – 11u + 24 = 0 where u = (x2 – 1) the first awnser, a.</span>
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2 years ago
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Verify the given linear approximation at a = 0. Then determine the values of x for which the linear approximation is accurate to
nikklg [1K]

Answer:

Part 1)

See Below.

Part 2)

\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)

Step-by-step explanation:

Part 1)

The linear approximation <em>L</em> for a function <em>f</em> at the point <em>x</em> = <em>a</em> is given by:

\displaystyle L \approx f'(a)(x-a) + f(a)

We want to verify that the expression:

1-36x

Is the linear approximation for the function:

\displaystyle f(x) = \frac{1}{(1+9x)^4}

At <em>x</em> = 0.

So, find f'(x). We can use the chain rule:

\displaystyle f'(x) = -4(1+9x)^{-4-1}\cdot (9)

Simplify. Hence:

\displaystyle f'(x) = -\frac{36}{(1+9x)^{5}}

Then the slope of the linear approximation at <em>x</em> = 0 will be:

\displaystyle f'(1) = -\frac{36}{(1+9(0))^5} = -36

And the value of the function at <em>x</em> = 0 is:

\displaystyle f(0) = \frac{1}{(1+9(0))^4} = 1

Thus, the linear approximation will be:

\displaystyle L = (-36)(x-(0)) + 1 = 1 - 36x

Hence verified.

Part B)

We want to determine the values of <em>x</em> for which the linear approximation <em>L</em> is accurate to within 0.1.

In other words:

\displaystyle \left| f(x) - L(x) \right | \leq 0.1

By definition:

\displaystyle -0.1\leq f(x) - L(x) \leq 0.1

Therefore:

\displaystyle -0.1 \leq \left(\frac{1}{(1+9x)^4} \right) - (1-36x) \leq 0.1

We can solve this by using a graphing calculator. Please refer to the graph shown below.

We can see that the inequality is true (i.e. the graph is between <em>y</em> = 0.1 and <em>y</em> = -0.1) for <em>x</em> values between -0.179 and -0.178 as well as -0.010 and 0.012.

In interval notation:

\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)

4 0
2 years ago
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