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spin [16.1K]
2 years ago
14

If the manager at first city bank surveys a sample of 100 customers to determine how many miles they live from the​ bank, is the

mean travel distance for this sample considered a parameter or a​ statistic? explain.
Mathematics
1 answer:
padilas [110]2 years ago
3 0
The answer to this question would be  yes, they are parameter.

Parameter is a data that can show the tendency of the sample. The example would be mean, mode, median. The parameter can be used to show how much similarity or differences between two sample. 
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Which expression represents the product of 3 and (5/4n + 1.8)
SashulF [63]
Answer: D


you have to distribute
3 times 5/4n = 3.75n
3 times 1.8 = 5.4
you can’t add both products because they don’t have like terms
3.75n + 5.4
3 0
2 years ago
What is the simplest form of 2sqrt2/sqrt3-sqrt2?
Alchen [17]

Answer:

2 sqr 6+4 or A

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Fiona wrote the linear equation y = y equals StartFraction 2 over 5 EndFraction x minus 5.x – 5. When Henry wrote his equation,
xeze [42]

Answer:

D. x-\frac{5}{2}y =  \frac{25}{2}

Step-by-step explanation:

Given

y = \frac{2}{5}x - 5

Required

Determine its equivalent

<em>From the list of given options, the correct answer is</em>

x - \frac{5}{2}y = \frac{25}{2}

This is shown as follows;

y = \frac{2}{5}x - 5

Multiply both sides by \frac{5}{2}

\frac{5}{2} * y = \frac{5}{2} * (\frac{2}{5}x - 5)

Open Bracket

\frac{5}{2} * y = \frac{5}{2} * \frac{2}{5}x - \frac{5}{2} *5

\frac{5}{2}y = x - \frac{25}{2}

Subtract x from both sides

\frac{5}{2}y - x = x -x - \frac{25}{2}

\frac{5}{2}y - x = - \frac{25}{2}

Multiply both sides by -1

-1 * \frac{5}{2}y - x * -1 = - \frac{25}{2} * -1

-\frac{5}{2}y + x =  \frac{25}{2}

Reorder

x-\frac{5}{2}y =  \frac{25}{2}

<em>Hence, the correct option is D</em>

x-\frac{5}{2}y =  \frac{25}{2}

9 0
2 years ago
Read 2 more answers
The range of scores in each interval of a grouped frequency distribution is called the
tamaranim1 [39]
The answer is class intervals. A big set of data are grouped into different classes to get a hint of the distribution, and the range of such class of data is known as the Class Interval. In other words, these are range of scores in a group frequency distribution. Class intervals are commonly equal in width and are mutually exclusive. The middle of an interval is called a class mark and the ends of a class interval are called class limits. To calculate the class interval, divide the range by the number of classes. 
3 0
2 years ago
The cabin of a business jet has a cabin height 5 feet 9 inches high. If a business traveler’s height is N(5'10", 2.7"), what per
klio [65]

Answer:

0.6443 = 64.43% of the business travelers will have to stoop

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Each feet is 12 inches

So

5'9'' = 5*12 + 9 = 69

5'10'' = 5*12 + 10 = 70

\mu = 70, \sigma = 2.7

What percentage of the business travelers will have to stoop?

This is 1 subtracted by the pvalue of Z when X = 69. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{69 - 70}{2.7}

Z = -0.37

Z = -0.37 has a pvalue of 0.3557.

1 - 0.3557 = 0.6443

0.6443 = 64.43% of the business travelers will have to stoop

3 0
2 years ago
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