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2 years ago

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8,900 incoming freshman to a university take an entrance exam, with the top 10% being offered admission to the university's hono

rs program. The average test score is 78%, with a standard deviation of 11%. Use a calculator to find what the student must score to be invited to join the honors program if only 65 scores are looked at to determine the honors admissions requirement.

1 answer:

Drupady [299]2 years ago

4 0

Answer:

The student must score 79.75% to be invited to join the honors program.

Step-by-step explanation:

Let <em>X</em> denote the score of a freshman in the entrance exam.

It is provided that the average test score is 78%, with a standard deviation of 11%.

It is provided that the top 10% being offered admission to the university's honors program.

Let <em>x</em> denote the score eligible for being offered admission to the university's honors program.

Then, P (X ≤ x) = 0.90.

Then P (Z < z) = 0.90.

The corresponding <em>z</em>-score is, 1.28.

*Use a <em>z</em>-table<em>.</em>

Compute the value of <em>x</em> as follows:

$z=\frac{x-\mu}{\sigma/\sqrt{n}}\\\\1.28=\frac{x-78}{11/\sqrt{65}}\\\\x=78+(1.28\times \frac{11}{\sqrt{65}})\\\\x=79.75\%$

Thus, the student must score 79.75% to be invited to join the honors program.

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Answer:

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Answer:

answer is

$-0.245 \pm2.160(0.205)$

Step-by-step explanation:

After working this way for 6 months he takes a simple random sample of 15 days. He records how long he walked that day (in hours) as recorded by his fitness watch as well as his billable hours for that day as recorded by a work app on his computer.

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David proved the Law of Cosines with reference to ∆ABC using a different method. Arrange the steps of his proof in the correct s

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Answer: We can arrange the steps with help of below explanation.

Step-by-step explanation:

Here ABC is a triangle,

Draw a perpendicular from BD to side AC ( construction)

where $D\in AC$

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cos C =CD/ BC

CD= a cos C

Subtracting this from the side b, we see that

DA= b-acos C

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sin C =BD / a

BD = a sin C

In the triangle ADB, applying the Pythagorean Theorem

$c^2 =BD^2 +DA^2$

Substituting for BD and DA from (2) and (3)

$c^2 =(asinC)^2 +(b-acosC)^2$

⇒ $c^2 =a^2sin ^2C+b^2-2ab cosC+a^2 cos ^2C$ ( On simplification)

⇒ $c^2 =a^2sin ^2C+a^2 cos ^2C+b^2-2abcos C$

⇒ $c^2=a^2(sin^2C+cos^2C) +b^2-2abcosC$

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2 years ago

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Answer:

3rd option: B(C)= 1.79C +86.03

Step-by-step explanation:

Total bill

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Let the cost of other groceries be G, and the cost of cans be X.

Given that number of cans= C,

Total bill= XC +G

If 2 cans were purchased,

2X+G= 89.61 -----(1)

If 5 cans were purchased,

5X +G= 94.98 -----(2)

(2) -(1):

(5X +G) -(2X +G)= 94.98 -89.61

5X +G -2x -G= 5.37

3X= 5.37

X= 5.37 ÷3 <em>(</em><em>÷</em><em>3</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

X= 1.79

Subst. X= 1.79 into (1):

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G= 86.03 <em>(</em><em>simplify</em><em>)</em>

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