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erica [24]
2 years ago
6

8,900 incoming freshman to a university take an entrance exam, with the top 10% being offered admission to the university's hono

rs program. The average test score is 78%, with a standard deviation of 11%. Use a calculator to find what the student must score to be invited to join the honors program if only 65 scores are looked at to determine the honors admissions requirement.
Mathematics
1 answer:
Drupady [299]2 years ago
4 0

Answer:

The student must score 79.75% to be invited to join the honors program.

Step-by-step explanation:

Let <em>X</em> denote the score of a freshman in the entrance exam.

It is provided that the average test score is 78%, with a standard deviation of 11%.

It is provided that the top 10% being offered admission to the university's honors program.

Let <em>x</em> denote the score eligible for being offered admission to the university's honors program.

Then, P (X ≤ x) = 0.90.

Then P (Z < z) = 0.90.

The corresponding <em>z</em>-score is, 1.28.

*Use a <em>z</em>-table<em>.</em>

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma/\sqrt{n}}\\\\1.28=\frac{x-78}{11/\sqrt{65}}\\\\x=78+(1.28\times \frac{11}{\sqrt{65}})\\\\x=79.75\%

Thus, the student must score 79.75% to be invited to join the honors program.

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Select all of the following true statements if R = real numbers, Z = integers, and W = {0, 1, 2, ...}.
PSYCHO15rus [73]
We can start solving this problem by first identifying what the elements of the sets really are.

R is composed of real numbers. This means that all numbers, whether rational or not, are included in this set.

Z is composed of integers. Integers include all negative and positive numbers as well as zero (it is essentially a set of whole numbers as well as their negated values).

W on the other hand has 0,1,2, and onward as its elements. These numbers are known as whole numbers.

W ⊂ Z: TRUE. As mentioned earlier, Z includes all whole numbers thus W is a subset of it.

R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.

0 ∈ Z: TRUE. Zero is indeed an integer thus it is an element of Z.

∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are <u>not</u> an element of R).

{0,1,2,...} ⊆ W: TRUE. The set on the left is exactly what is defined on the problem statement for W. (The bar below the subset symbol just means that the subset is not strict, therefore the set on the left can be <u>equal</u> to the set on the right. Without it, the statement would be false since a strict subset requires that the two sets should not be equal).

-2 ∈ W: FALSE. W is just composed of whole numbers and not of its negated counterparts.
3 0
2 years ago
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Joan is building a sandbox in the shape of a regular pentagon. The perimeter of the pentagon is 35y4 – 65x3 inches. What is the
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From the choices above the answer would be: D 7y^4-13x^3 inches
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2 years ago
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Train A and train B stops at Swindon at 10:30 . Train A stops every twelve minutes and train B stops every 14 Mins , when do the
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Answer: at 11:54

Step-by-step explanation:

Let's define the 10:30 as our t = 0 min.

We know that Train A stops every 12 mins, and Train B stops every 14 mins, they will stop at the same time in the least common multiple of 12 and 14.

To find the least common multiple of two numbers, we must do:

LCM(a,b) = a*b/GCD(a,b)

Where GCD(a, b) is the greatest common divisor of a and b.

In this case the only common divisior of 12 and 14 is 2.

So we have:

LCM(12, 14) = 12*14/2 = 84.

Then the both trains will stop 84 minutes after 10:30

one hour has 60 mins, so we can write 84 minutes as:

1 hour and 24 minutes = 1:24

Then they will stop at the same time at 10:30 + 1:24 = 11:54

4 0
1 year ago
In the parallelogram AXYZ, line segment AT = 4y – 2, line segment TY = 6x -12, line segment TX = 14, line segment ZT = 2x + 12.
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In a parallelogram diagonals bisect each other,
=>AT=TX=>4y-2=14=>4y=14+2=>4y =16=>y=16/4=4
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8 0
1 year ago
Solve the equation, keeping the value for x as an improper fraction. 23x = − 12x + 5 1.Isolate the variable by adding 12x to bot
kogti [31]

Answer:

x=\frac{30}{7}

Step-by-step explanation:

We have been given an equation \frac{2}{3}x=-\frac{1}{2}x+5. We are asked to solve our given equation.

First of all, we will add \frac{1}{2}x on both sides of equation to separate x variable on one side of equation.

\frac{2}{3}x+\frac{1}{2}x=-\frac{1}{2}x+\frac{1}{2}x+5

\frac{2}{3}x+\frac{1}{2}x=5

Now, we will make a common denominator.

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Add numerators:

\frac{4+3}{6}x=5

\frac{7}{6}x=5

Upon multiply both sides of our equation by \frac{6}{7}, we will get:

\frac{6}{7}*\frac{7}{6}x=5*\frac{6}{7}

x=\frac{5*6}{7}

x=\frac{30}{7}

Therefore, the solution for our given equation is x=\frac{30}{7}.

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1 year ago
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