Answer, step-by-step explanation:
A. With the previous exercise we can deduce that there is the situation of a number of sales in a grocery store, the relative frequency for the number of units sold, is shown below:
units sold. relative frequency. Acumulative frequency. interval of random numbers
30. 0.16. 0.16. 0.00 <0.16
40. 0.24. 0.4. 0.16 <0.4
50. 0.3. 0.7. 0.4 <0.7
60. 0.2. 0.9. 0.7<09
70. 0.1. 1. 0.9<1
B. For the next point, they give us some random numbers and then it is compared with the simulation of 10 days in sales:
random Units
number. sold
0.12. 30
0.96. 70
0.53. 50
0.80. 60
0.95. 70
0.10. 30
0.40. 50
0.45. 50
0.77. 60
0.29. 40
the two lists are compared so that opposite each one is the result of the simulation
Answer:
Commissions:
Accessoriy: $2
Phone: $9
Step-by-step explanation:
18p + 21a = 204
6p + 14a = 82
21a = 42
a = 2
p = [82 - 14(2)]/6 = 9
Answer:
you can divide the answers by the time duration of the exam and get your answer
Step-by-step explanation:
Answer: y+5 = 9/8(x-9)
Step-by-step explanation: Point-slope form is written in y-y1 = m(x-x1) so when you put in (9,-5) in the y1 and x1 spots and substitute the slope 9/8 in for m you get the point-slope form.
This problem has several items. So, let's solve it step by step.
1. Compare the graphs of the logarithmic functions f(x)=log7x and g(x)=log4x.
In the Figure below, we have tha graph of the two functions. The graph in red is
and the graph in blue is
. The x-intercept of
is:

On the other hand, the x-intercept of
is:

Each graph begins in the fourth quadrant and is increasing quickly. As the graph crosses the x-axis at each x-intercept, each graph does not increase as fast. The graph continues to increase slowly throughout the first quadrant.
2. For what values of x is f=g
We can find this answer by taking this equation:

As you can see this is an absurd result since 7 is not equal to 4. The conclusion is that the function
is always different from
, that is, 
3. For what values f>g
From the graph, we can see that the red function is always greater than the blue function. Therefore, 