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EastWind [94]
2 years ago
6

How might you prove your observations about the slope of a midsegment in part d using algebra and x- and y-coordinates? Briefly

outline an approach using what you know about midpoints and parallel lines. Use the figure you created in GeoGebra to guide you.
Mathematics
2 answers:
ioda2 years ago
4 0

Answer: I can use variables to represent the coordinates of the vertices for a general triangle ABC. then I can calculate the midpoints of the sides in terms of the same variables, and calculate the slope of each midsegment showing that the expression for the slope of a midsegment is the same as the expression for the slope of the third side of the triangle proves that the two are parallel.

Step-by-step explanation: this is word for word btw!

Lesechka [4]2 years ago
3 0

Answer:

Answer: I can use variables to represent the coordinates of the vertices for a general triangle ABC. then I can calculate the midpoints of the sides in terms of the same variables, and calculate the slope of each midsegment showing that the expression for the slope of a midsegment is the same as the expression for the slope of the third side of the triangle proves that the two are parallel.

Step-by-step explanation: this is word for word btw!

Step-by-step explanation:

THANKS U PLATO

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Transform the equation to isolate x: ax = bx + 1. How is
shepuryov [24]

Answer:

x=\frac{1}{a-b}

The value of x is inversely proportional to the difference of <em>a</em> and <em>b</em>.

Step-by-step explanation:

The given expression is ax-bx+1

We factor the left hand side to get:

(a-b)x=1

We divide both sides by: a-b

x=\frac{1}{a-b}

Observe that the difference of a and b is in the denominator.

The whole is of the form: x\propto \frac{1}{a-b}

The value of x is inversely proportional to the difference of <em>a</em> and <em>b</em>.

6 0
2 years ago
Read 2 more answers
What is the x-intercept of the line with the equation -2x+1/2y=18
Mkey [24]

The x-intercept is a point on the x-axis.
y=0 at every point on the x-axis.

                                       -2x + 1/2(0) = 18

                                       -2x              =  18

Divide each side by  -2 :    x = -9

7 0
2 years ago
A sample of size 60 from one population of weights had a sample average of 10.4 lb. and a sample standard deviation of 2.7 lb. A
Olegator [25]

Answer:

z=  0.278

Step-by-step explanation:

Given data

n1= 60 ; n2 = 100

mean 1= x1`= 10.4;     mean 2= x2`= 9.7

standard deviation  1= s1= 2.7 pounds ;  standard deviation 2= s2 = 1.9 lb

We formulate our null and alternate hypothesis as

H0 = x`1- x`2 = 0 and H1 = x`1- x`2 ≠ 0 ( two sided)

We set level of significance α= 0.05

the test statistic to be used under H0 is

z = x1`- x2`/ √ s₁²/n₁ + s₂²/n₂

the critical region is z > ± 1.96

Computations

z= 10.4- 9.7/ √(2.7)²/60+( 1.9)²/ 100

z= 10.4- 9.7/ √ 7.29/60 + 3.61/100

z= 0.7/√ 0.1215+ 0.0361

z=0.7 /√0.1576

z= 0.7 (0.396988)

z= 0.2778= 0.278

Since the calculated value of z does not fall in the critical region so we accept the null hypothesis H0 = x`1- x`2 = 0  at 5 % significance level. In other words we conclude that the difference between mean scores is insignificant or merely due to chance.

3 0
2 years ago
Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps
Firdavs [7]
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions. 

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the 

   x²y = -4 ... (I)

Condition 2: Real parts are the same

   x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

   x²y = -4 ... (I)
   x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

   y = -3 - x² ... (II)

Substituting into equation (I)

   x²y = -4 ... (I)
   x²(-3 - x²) = -4
   -3x² - x⁴ = -4
   x⁴ + 3x² - 4 = 0
   (x² + 4)(x² - 1) = 0
   (x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

   y = -3 - x² ... (II)
   y = -3 - (±1)²
   y = -3 - 1
   y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

   -3 + ix²y 
   = -3 + i(±1)²(-4)
   = -3 - 4i

   x² + y + 4i
   = (±1)² - 4 + 4i
   = 1 - 4 + 4i
   = -3 + 4i

They result in conjugates
4 0
2 years ago
Read 2 more answers
A broker has a four-year contract to manage a rental unit for an investor. He is to receive 50% of the first month's rent and 5%
Alex777 [14]

Answer:

Step-by-step explanation:

600 X .50 = 300.00 1st month

600 X .05 = 30.00 47 months

30 X 47 = 1,410

1,410 + 300 = 1,710 (final answer)

8 0
2 years ago
Read 2 more answers
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