Ask question

Ask question

All categories

1 year ago

14

A collection of 108 coins containing only quarters and nickels is worth $21. A table titled Coin Collection showing Number of Co

ins, Value, and Total. The first row shows Nickels, and has n, 0.05, and 0.05 n. The second row shows, Quarters, and has q, 0.25, and 0.25 q. The third row shows total, and has not entries. Which value could replace q on the chart? 21 108 21 – n 108 – n

2 answers:

harina [27]1 year ago

8 0

Answer:

q = 108-n

Step-by-step explanation:

Given: 108 coins containing only quarters and nickels

q = 108-n

since total number of coins is 108, and n= number of nickels

If you want to know how many of each kind of coin, read on:

First solve the number of quarters and nickels.

If all 108 coins are quarters, the value is 108*0.25 = $27

Since this value exceed the actual by 27-21 = $6,

we replace a number of quarters by nickels.

Each replacement will reduce the value by 25 - 5 = 20 cents = 0.2 dollars.

So it will take 6/0.2 = 30 replacements.

Therefore there are 108-35 = 78 quarters and 30 nickels.

Kaylis [27]1 year ago

7 0

Answer:

108-n

Step-by-step explanation: just did it

You might be interested in

comparing permutations to combinations for the same set of parameters you would have more combinations than permutations true or

ella [17]

Let a set of $n$ elements.
We can find $n!$ (factorial) of the $n$ element.
However, combination of the element lead to less than $n!$ possibilities.
(combining like adding or multiplying)
So the proposition is false.

6 0

2 years ago

Read 2 more answers

What are two partial products you could add to find 990x37

kifflom [539]

25320+11310=36,630 or 12,430+24,200=36,630

4 0

1 year ago

Read 2 more answers

Write the denominator of the rational number257/500 in the form 2 m x 5 n , m and n are negative integers Hence write its decima

maw [93]

Answer:

0.514

Step-by-step Explantion:

Denominator = 500 = 2^2 * 5^3

257/500 = 257/2^2*5^3 = 2*257/2*2^2*5^3 = 514/2^3*5^3 = 514/(2*5)^3 = 514/10^3 = 0.514

6 0

1 year ago

Point B is in the interior of ∠AOC, m∠AOC = 108°, m∠AOB = 3m∠BOC. Find m∠AOB.

valentinak56 [21]

If point is the interior of <AOC ,
then m<AOB + m<BOC = m< AOC ( angle addition postulate ) eq 1
(3m<BOC ) + m <BOC = m <AOC { m<AOB = 3m<BOC)
4m <BOC = 108
m<BOC = 27

m<AOB + m <BOC = m < AOC
m<AOB = 108 - 27
m <AOB = 81

6 0

2 years ago

Read 2 more answers

A study of 25 graduates of four-year public colleges revealed the mean amount owed by a student in student loans was $55,051. Th

Kitty [74]

Answer:

a

The 90% confidence interval is $52561.13 < \mu < 57540.8$

b

Confidence interval for the population men between <u>$52561.13</u> up to <u>$57540.8</u>

Step-by-step explanation:

From the question we are told that

The sample size is $n = 25$

The sample mean is $\= x = \$ 55,051$

The standard deviation is $\sigma = \$ 7,568$

Given that the confidence level is 90% then the level of confidence is mathematically represented as

$\alpha = 100 -90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table the values is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{ \sigma }{\sqrt{n} }$

substituting values

$E = 1.645 * \frac{ 7568}{ \sqrt{ 25} }$

$E = 2489.9$

The 90% confidence interval is mathematically evaluated as

$\= x -E < \mu < \= x +E$

substituting values

$55051 - 2489.8 < \mu < 55051 + 2489.8$

$52561.13 < \mu < 57540.8$

6 0

2 years ago