v=gt,
Initial value when time t=0, v=g*0=0.
t=0 s, v=0 m/s means that object’s initial velocity 0 m/s.
v=gt, and g is a constant g=9.8 m/s². We can write v=9.8*t.
Rate of change 9.8 means the acceleration due to gravity is 9.8 m/s².
Answer: C. The initial value is 0. That means that object’s initial velocity 0 m/s. The rate of change is 9.8. That means the acceleration due to gravity is 9.8 m/s2.
Answer:
The value of the account in the year 2009 will be $682.
Step-by-step explanation:
The acount's balance, in t years after 1999, can be modeled by the following equation.
In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.
$330 in an account in the year 1999
This means that 
$590 in the year 2007
2007 is 8 years after 1999, so P(8) = 590.
We use this to find r.
Applying ln to both sides:
Determine the value of the account, to the nearest dollar, in the year 2009.
2009 is 10 years after 1999, so this is A(10).
The value of the account in the year 2009 will be $682.
Elsa's answer is incorrect since there is a solution of the given equation. In the given logarithmic problem, we need to simplify the problem by transposing log2(3x+5) in the opposite side. The equation will now be log2x-log2(3x+5)=4. Using properties of logarithm, we further simplify the problem into a new form log (2x/6x+10)=4. Then transform the equation into base form 10^4=(2x/6x+10) and proceed in solving for x value which is equal to 1.667.
Answer: ∠Z ≅ ∠G and XZ ≅ FG or ∠Z ≅ ∠G and XY ≅ FE are the additional information could be used to prove that ΔXYZ ≅ ΔFEG using ASA or AAS.
Step-by-step explanation:
Given: ΔXYZ and ΔEFG such that ∠X=∠F
To prove they are congruent by using ASA or AAS conruency criteria
we need only one angle and side.
1. ∠Z ≅ ∠G(angle) and XZ ≅ FG(side)
so we can apply ASA such that ΔXYZ ≅ ΔFEG.
2. ∠Z ≅ ∠G (angle)and ∠Y ≅ ∠E (angle), we need one side which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
3. XZ ≅ FG (side) and ZY ≅ GE (side), we need one angle which is not present here.∴we can not apply ASA such that ΔXYZ ≅ ΔFEG.
4. XY ≅ EF(side) and ZY ≅ FG(side), not possible.
5. ∠Z ≅ ∠G(angle) and XY ≅ FE(side),so we can apply ASA such that
ΔXYZ ≅ ΔFEG.
