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dolphi86 [110]
2 years ago
10

A rope is 66 feet long. It is cut into two pieces such that one piece is half the length of the other. What is the length of the

longer piece of rope?
a.22 feet
b.26 feet
c.33 feet
d.44 feet
Mathematics
2 answers:
dedylja [7]2 years ago
7 0
So if one bit of the length, is half the size of the other bit then we can make the following equation, for x being the length of rope:

x + 2x = 66
3x = 66
x = 22

That is the length, of the smaller one (half the big one), so 2x = 44. Hence d) is your answer.

Hope I helped!
34kurt2 years ago
5 0
Let's say the two piece's lengths are x and y

so x+y=66

then we are told that "one piece is half the length of the other"
so x = (1/2)y

we plug this into the first equation and get
(1/2)y + y = 66
or
1.5 y = 66

divide both sides by 1.5 to get y alone
y = 66 / 1.5 = 44

we can check to see if y is the longer one by finding x
x = 66 - y = 66 - 44 = 22

44 is bigger than 22
therefore 44 is the length of the longer piece
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Step-by-step explanation:

Data given and notation  

\bar X=5.0611 represent the sample mean

\sigma=0.2803 represent the population standard deviation for the sample  

n=42 sample size  

\mu_o =5 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

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Alternative hypothesis:\mu \neq 5  

If we analyze the size for the sample is > 30 but and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

P-value

Since is a two sided test the p value would be:  

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Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

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