In this question , we have a graph given, and we have to find the x coordinate of the intersection point .
From the graph , the input value is approximately 3.3 .
In the graph,
And for g(x), we need the slope and y intercept .
Slope is the ratio of rise and run .
Here rise equals 3 units and run equals 2 units. And the graph touch the y axis at -2 .
So the equation of g(x) is
We need to do
Substituting the values of the two functions, we will get
Adding 2 to both sides
Cross multiplication
So the input value is 3.3 approx
Hi there
If the amount deposited at (end) of each year, use the formula of the (future/present) value of annuity ordinary
If the amount deposited at the (beginning) of each year use the formula of the (future/present) value of annuity due
So
FvAo=5,000×(((1+0.0245)^(5)−1)
÷(0.0245))
=26,255.38...answer
Hope it helps
Answer:
200
Step-by-step explanation:
Given Arithmetic sequence is: 26, 28, 30,...
First term a = 26
Common Difference d = 2
n = 88
Answer:
i know im vv late but i dont want anyone to get it wrong. anyway if your on e2020 i believe the correct answer is
D. The company cannot provide lunch for all 20 employees and use the entire budget because there is no solution to the system of equations mc019-r+t=20 and 5r+5t=150
Step-by-step explanation:
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin.
<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>
<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>
<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>
<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>
<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>
<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>
<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>
<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>
<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
