Answer:
y-intercept of the line MN = 2
Standard form of the equation ⇒ x + y = 2
Step-by-step explanation:
Coordinates of the ends of a line MN → M(-3, 5) and N(2, 0)
Slope of a line = 
= 
= -1
Equation of the line MN passing through (-3, 5) and slope = -1,
y - 5 = (-1)(x + 3)
y - 5 = -x - 3
y = -x + 2
This equation is in the y-intercept form,
y = mx + b
where m = slope of the line
b = y-intercept
Therefore, y-intercept of the line MN = 2
Equation in the standard form,
x + y = 2
Mercury is larger because 4,878 km vs 1736.5 x 2 = 3473 km. And since radius is half of the diameter we are multiplying by 2. So in short, Mercury is larger. Hope this helps!!!
You have to use the Geometric Mean for triangles to find x. Our form will look like this:
which simplifies to
. Cross multiply to get
. Therfore, x = 4. Usually when we take the square root of a number we will end up with both the principle (positive) root and the negative one as well. But since the 2 things in math that will never EVER be negative are time and distance/length, we will not consider the -4. x = 4
Answer:
a) This is an Observational Study because in this kind of study investigators observe subjects and measure variables of interest without assigning treatments to the subjects. Here, the Gilham et al. (2005) studied two different groups where no treatment or intervention was done. These groups were independent of each other.
b) proportions of children with significant social activity in children with acute lymphoblastic leukemia = 1020/1272 = 0.80
proportions of children with significant social activity in children without acute lymphoblastic leukemia = 5343/6238 = 0.86
c) Odds ratio can be calculated using the following formula:
OR= \frac{a/b}{c/d}
where: a - Number in exposed group with positive outcome(here this means number of children with significant social activity associated with acute lymphoblastic leukemia)
b- Number of children without social activity having with acute lymphoblastic leukemia
c- Number of children with social activity having without acute lymphoblastic leukemia
d- Number of children without social activity having without acute lymphoblastic leukemia
OR= \frac{1020/252}{5343/895}
OR= 0.6780
d) The 95% confidence interval of this Odds Ratio is 0.5807 to 0.7917.
e) Since the odds ratio lies in this confidence interval indicate that the amount of social activity is associated with acute lymphoblastic leukemia. The children with more social activity have a higher occurrence of acute lymphoblastic leukemia.
Answer:
1 : 9.75 * 10⁷
Step-by-step explanation:
To find n, we have to divide the real distance by the scale distance. This is 7.8 * 10⁸ / 8 = 0.975 * 10⁸ = 9.75 * 10⁷ which means that the ratio is 1 : 9.75 * 10⁷.
