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mash [69]
1 year ago
14

The table below shows the amount of lemon juice and sugar needed to make three different-sized batches of lemonade using the sam

e recipe. Lemon juice ( mL mLstart text, m, L, end text) Sugar ( g gstart text, g, end text) Batch A 500 500500 200 200200 Batch B 750 750750 300 300300 Batch C 1500 15001500 600 600600 Write an equation to describe the relationship between j jj, the amount of lemon juice in mL mLstart text, m, L, end text, and s ss, the amount of sugar in g gstart text, g, end text.
Mathematics
1 answer:
Amiraneli [1.4K]1 year ago
3 0

Answer:

The equation is:

        j/g=5/2

Or, what is equivalent:

        j=5g/2

Explanation:

This is the<em> table</em> that <em>shows the amount of lemon juice and sugar needed to make three different-sized batches of lemonade using the same recipe</em>:

                        Lemon juice (mL)       Sugar (g)

Batch A               500                            200

Batch B                750                            300

Batch C              1500                            600

You need to write an <em>equation to describe the relationship between j, the amount of lemon juice in mL and s, the amount of sugar in g</em>.

Calculate some ratios, to determine the kind of relation between the amount of juice and the amount of sugar in the recipe.

  • Batch A: lemon juice / sugar = 500 / 200 = 5/2

  • Batch B: lemon juice / sugar = 750/300 = 5/2

  • Batch C:  lemon juice / sugar = 1500/600 = 5/2

Hence, the amount of juice, j, and the amound of sugar, s, are proportional and the constant of proportionality is 5/2. From this, the equation is:

        j/g=5/2

Or, what is equivalent (solving for j):

        j=5g/2

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Answer:

Option b. None is the correct option.

The Answer is 63%

Step-by-step explanation:

To solve for this question, we would be using the z score formula

The formula for calculating a z-score is given as:

z = (x-μ)/σ,

where

x is the raw score

μ is the population mean

σ is the population standard deviation.

We have boxes X and Y. So we will be combining both boxes

Mean of X = 100 lb

Mean of Y = 5 lb

Total mean = 100 + 5 = 105lb

Standard deviation for X = 1 lb

Standard deviation for Y = 0.5 lb

Remember Variance = Standard deviation ²

Variance for X = 1lb² = 1

Variance for Y = 0.5² = 0.25

Total variance = 1 + 0.25 = 1.25

Total standard deviation = √Total variance

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Solving our question, we were asked to find the percent of filled boxes weighing between 104 lb and 106 lb are to be expected. Hence,

For 104lb

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z = 104 - 105 / √25

z = -0.89443

Using z score table ,

P( x = z)

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For 1061b

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P( x = z)

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