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mr Goodwill [35]

1 year ago

10

The equation $y = -16t^2 + 80t$ describes the height (in feet) of a projectile launched from the ground at 80 feet per second. A

t what $t$ will the projectile reach 36 feet in height for the first time? Express your answer as a decimal rounded to the nearest tenth.

1 answer:

Salsk061 [2.6K]1 year ago

4 0

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Which of these lists correctly orders the binary numbers from smallest to largest? Choose 1 answer: Choose 1 answer: (Choice A)

aleksandr82 [10.1K]

Try using photomath it will explain on what to do.

5 0

1 year ago

A thin sheet of ice is in the form of a circle. If the ice is melting in such a way that the area of the sheet is decreasing at

elena-14-01-66 [18.8K]

Answer:

dx/dt = 0,04 m/sec

Step-by-step explanation:

Area of the circle is:

A(c) =π*x² where x is a radius of the circle

Applying differentiation in relation to time we get:

dA(c)/dt = π*2*x* dx/dt

In this equation we know:

dA(c)/dt = 0,5 m²/sec

And are looking for dx/dt then

0,5 = 2*π*x*dx/dt when the area of the sheet is 12 m² (1)

When A(c) = 12 m² x = ??

A(c) = 12 = π*x² ⇒ 12 = 3.14* x² ⇒ 12/3.14 = x²

x² = 3,82 ⇒ x = √3,82 ⇒ x = 1,954 m

Finally plugging ths value in equation (1)

0,5 = 6,28*1,954*dx/dt

dx/dt = 0,5 /12.28

dx/dt = 0,04 m/sec

7 0

1 year ago

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If a(x) = 3x + 1 and b (x) = StartRoot x minus 4 EndRoot, what is the domain of (b circle a) (x)?

kiruha [24]

Answer:

$[1,\infty)$

Step-by-step explanation:

$b(x)=\sqrt{x-4}$

$a(x)=3x+1$

Since we want to know the domain of $(b \circ a)(x)$ , let's first consider the domain of the inside function, that is, that of $a(x)=3x+1$ . Every polynomial function has domain all real numbers.

So we can plug anything for function $a$ and get a number back.

Now the other function is going to be worrisome because it has a square root. You cannot take square root of negative numbers if you are only considering real numbers which that is the case with most texts.

Let's find $(b \circ a)(x)$ and simplify now.

$(b \circ a)(x)$

$b(a(x))$

$b(3x+1)$

$\sqrt{(3x+1)-4}$

$\sqrt{3x+1-4}$

$\sqrt{3x-3}$

Now again we can only square root positive or zero numbers so we want $3x-3 \ge 0$ .

Let's solve this to find the domain of $(b \circ a)(x)$ .

$3x-3 \ge 0$

Add 3 on both sides:

$3x \ge 3$

Divide both sides by 3:

$x \ge 1$

So we want $x$ to be a number greater than or equal to 1.

The option that says this is $[1,\infty)$

-------------------------------

Give an example why option A fails:

A number in the given set is -2.

$a(x)=3x+1$

$b(x)=\sqrt{x-4}$

So $a(-2)=3(-2)+1=-6+1=-5$ and $b(-5)=\sqrt{-5-4}=\sqrt{-9} \text{ which is not real}$ .

Give an example why option B fails:

A number in the given set is 0.

$a(x)=3x+1$

$b(x)=\sqrt{x-4}$

So $a(0)=3(0)+1=0+1=1$ and $b(1)=\sqrt{1-4}=\sqrt{-3} \text{ which is not real}$ .

Give an example why option D fails:

While all the numbers in set D work, there are more numbers outside that range of numbers that also work.

A number not in the given set that works is 3.

$a(x)=3x+1$

$b(x)=\sqrt{x-4}$

So $a(3)=3(3)+1=9+1=10$ and $b(1)=\sqrt{10-4}=\sqrt{6} \text{ which is real}$ .

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2 years ago

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A study was conducted to determine the mean birth weight of a certain breed of kittens. Consider the birth weights of kittens to

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3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.

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2 years ago

Complete the coordinate proof of the theorem. Given: A B C D is a parallelogram. Prove: The diagonals of A B C D bisect each oth

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Answer:

Step-by-step explanation:

THESE ARE THE CORRECT ANSWERS

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2 years ago

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