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2 years ago

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Which relation is a function of x? {(1, 2), (7, 6), (3, 2), (1, 0), (5, 6)} A 2-column table with 4 rows. Column 1 is labeled x

with entries 0, 0, 0, 0. Column 2 is labeled y with entries 2, negative 6, 9, negative 7. x = 3 y squared minus 7 On a coordinate plane, a graph curves up, then curves down, and then curves up again. please comment i cant see answers thank you! :)

2 answers:

inna [77]2 years ago

5 0

Answer: The answer is D . The graph

Step-by-step explanation: It was the answer given on Edge.

kramer2 years ago

5 0

Answer:d is answer

Step-by-step explanation:

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Use the graph to write an explicit function to represent the data and determine how much money Amy earned in week 5.

zalisa [80]

Answer:

3rd option

$f(n)=5(3)^{n-1}$

$f(5)=405$

Step-by-step explanation:

So we are given the following points:

(1,5)

(2,15)

(3,45)

(4,135)

This is a geometric sequence because there is a common ratio, 3. That is you can keep multiply 3 to a previous y-coordinate to get the next y-coordinate.

The formula for a geometric sequence is $f(n)=a_1 \cdot r^{n-1}$

where $a_1$ is the first term and r is the common ration.

So we have

$f(n)=5 \cdot (3)^{n-1}$ .

If you want to know the fifth term, just plug in 5:

$f(5)=5 \cdot (3)^{5-1}$

Simplifying:

$f(5)=5 \cdot 3^4$

$f(5)=5 \cdot 81$

$f(5)=405$

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1 year ago

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What is the length of the altitude of the equilateral triangle below?

Mazyrski [523]

ANSWER

The length of the altitude is $3\sqrt{3}$ units

<u>EXPLANATION</u>

The altitude of a triangle is the vertical height of the triangle.

From the diagram the altitude is $a$

Method 1: We can use Pythagoras theorem to find $a$

$6^2=a^2+3^2$

$6^2-3^2=a^2$

$36-9=a^2$

$27=a^2$

We take the square root of both sides,

$\sqrt{27}=a$

$\sqrt{9\times3}=a$

$\sqrt{9} \times \sqrt{3}=a$

$3\sqrt{3}=a$

Method 2 Using Trigonometry

$sin(60\degree)=\frac{a}{6}$

$6sin(60\degree)=a$

$a=6\times \frac{\sqrt{3}} {2}$

$a=3\sqrt{3}$

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2 years ago

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Stan's cookie recipe makes 242424 cookies and calls for exactly 384384384 sprinkles. He is wondering how many sprinkles (p)(p)le

arlik [135]

If these numbers are correct:

For every 242,424 cookies he needs 384,384,384 sprinkles. So how many sprinkles does he need for 606,060 cookies?

242,424/384,384,384 = 606,060/x

384,384,384 * 606,060 = 242,424 * x

232,959,999,767,040 = 242,424 * x

960,960,960 = x

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2 years ago

Of the 500 sample households in the previous exercise, 7 had three or more large-screen TVs. (a) The percentage of households in

likoan [24]

Answer:

a) The percentage of households in the town with three or more largescreen TVs is estimated as :

The best estimation for the population proportion is :

$\hat p=\frac{7}{500}=0.014$

And that represent the 1.4%.

b) And the 95% confidence interval would be given (0.00370;0.0243).

And the % would be between 0.37% and 2.43%.

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=7 represent the households with three or more large-screen TVs

$\hat p=\frac{7}{500}=0.014$ estimated proportion of households with three or more large-screen TVs

$\alpha=0.05$ represent the significance level (no given, but is assumed)

z would represent the statistic (variable of interest)

p= population proportion of households with three or more large-screen TVs

Part a

The percentage of households in the town with three or more largescreen TVs is estimated as :

The best estimation for the population proportion is :

$\hat p=\frac{7}{500}=0.014$

And that represent the 1.4%.

Part b

Yes is possible. We hav that $np>10$ and $n(1-p)>10$ so we have the assumption of normality to find the interval.

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.014 - 1.96 \sqrt{\frac{0.014(1-0.014)}{500}}=0.00370$

$0.014 + 1.96 \sqrt{\frac{0.014(1-0.014)}{500}}=0.0243$

And the 95% confidence interval would be given (0.00370;0.0243).

And the % would be between 0.37% and 2.43%.

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2 years ago

At 1:00 P.M., the the water level is 28 inches. the water level in a pool is 13 inches. At 1:30 P.M., the water level is 18 inch

Dmitrij [34]

Answer:

the answer is 19.667

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2 years ago

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