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2 years ago

The process of finding polynomials whose product equals a given polynomial is called

Mathematics

1 answer:

vekshin12 years ago

6 0

The process of finding polynomials whose product equals a given polynomial is called

Answer: The process of finding polynomials whose product equals a given polynomial is called factoring.

Factoring polynomials involves breaking up a polynomial into simpler terms (the factors) such that when the terms are multiplied together they are equal the original polynomial. Factoring helps to solve complex equations so they are easier to work with. For example, 4(x + 3) is the factored form of 4x + 12

(4 was “factored out” since it was a factor of both terms).

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If AD=20 and AC=3x+4, find the value of x. Then find AC and DC.<br><br> I don't understand.

Fofino [41]

<span>Using the information we have 3x+4=40 Do the same to each side of the equation to eliminate for x. 3x+4=40 Minus 4 from each side 3x=40-4 3x=36 Divide 3 from each side x=36/3 x=12 AC=3x+4 insert the value of x 3(12)+4=40 AC=40 AD=20</span>

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2 years ago

A circle has a radius of 5ft and an arc of length 7 ft is made by the intersection of the circle with a central angle. Which equ

Serggg [28]

Answer:

$\frac{q}{360}$ × π10 = 7

Explanation:

The formula to find arc length is $\frac{x}{360}$ × $\pi r^{2}$

Simply plug in radius and arc length to get your equation.

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2 years ago

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A plant can either have a smooth seed (p) or a rough seed (q). Rough seeds are recessive and smooth seeds are dominant. In a pop

adell [148]

To calculate this, the Hardy-Weinberg principle can be used:

p² + 2pq + q² = 1 and p + q = 1

where p and q are the frequencies of the alleles (p - dominant, q - recessive), and p², q² and 2pq are the frequencies of the genotypes.

a) Since 32 plants have rough seed (recessive genotype: q²) out of 100 plants in total, then

q² = 32/100 = 0.32

b) q = √q² = √0.32 = 0.56

c) Since p + q = 1, then

p = 1 - q = 1 - 0.56 = 0.44

d) 19 plants with rough seeds (recessive genotype: q²) in a population of 100 means that q² = 19/100 = 0.19

We need to calculate p (the allele frequency for smooth seeds).
We can find q because we know q²:

q = √q² = √0.19 = 0.44

Since p + q = 1, then

p = 1 - q = 1 - 0.4 = 0.56

3 0

2 years ago

A study determined that the average student who graduates takes 58 months to graduate from college with a bachelor’s degree and

Alona [7]

B is the answer a b c and d is the answer

7 0

2 years ago

A study is being conducted in which the health of two independent groups of ten policyholders is being monitored over a one-year

uysha [10]

Answer:

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

Step-by-step explanation:

We use two binomial trials to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of at least nine participants finishing the study in a group.

0.2 probability of a students dropping out. So 1 - 0.2 = 0.8 probability of a student finishing the study. This means that $p = 0.8$ .

10 students, so $n = 10$

We have to find:

$P(X \geq 9) = P(X = 9) + P(X = 10)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{10,9}.(0.8)^{9}.(0.2)^{1} = 0.2684$

$P(X = 10) = C_{10,10}.(0.8)^{10}.(0.2)^{0} = 0.1074$

$P(X \geq 9) = P(X = 9) + P(X = 10) = 0.2684 + 0.1074 = 0.3758$

0.3758 probability that at least nine participants complete the study in a group.

Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?

0.3758 probability that at least nine participants complete the study in a group. This means that $p = 0.3758$

Two groups, so $n = 2$

We have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.3758)^{1}.(0.6242)^{1} = 0.4691$

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

5 0

2 years ago

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