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Brilliant_brown [7]
2 years ago
8

each month for 7 months, Samuel mows 3 lawns. how many more laws does he need to mow before he has mowed 29 lawns

Mathematics
1 answer:
Kitty [74]2 years ago
5 0
Samuel started out with 21 mowed lawns. 7(months) x 3(lawns) = 21
If he mows 3 lawns per month, then he would have to mow lawns for another 3 months. 3 x 3 = 9. 
21 + 9 = 30
Although this is one mowed lawn over the objective, any less would not reach 29. 

I'm not really sure what the question is asking, so here's two answers:
He would have to mow lawns for another 3 months in order to mow 29 lawns.

Or, he would have to mow 8 more lawns.
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which of the sets shown includes the elements of set Z that both negative numbers and multiples of ?. Z={-34,-28,-16,-2,4,8,12,2
Ronch [10]

Answer:

multiples of 2

Step-by-step explanation:

6 0
2 years ago
Tia Veronica Pam and Lily are sisters. Tia is eight years old and she’s two years older than Pam. Pam is five years younger than
Nastasia [14]

Answer:

Pam (6 years), Tia(8 years), Veronica(11 years) , Lily (15 years)

Step-by-step explanation:

Age of Tia = 8 years

______________________________________________

Given Tia is  2 years older than Pam

mathematically

age  of Pam + 2 years = age of Tia

age  of Pam + 2 years = 8 years

age  of Pam  = 8 years- 2 years = 6 years

______________________________________________

Given Pam is five years younger than Veronica

we can infer that age of veronica is age of Pam + 5 more years

mathematically

age  of Pam + 5 years = age of Veronica

6 years + 5 years = age of Veronica

age  of Veronica   = 11 years

______________________________________________

Given Veronica is four years younger than Lily

we can infer that age of Veronica is (age of Lily - 4  years)

mathematically

age of Veronica = age of lily - 4 years

11 years = age of lily - 4 years

age of lily = 11 years + 4 years = 15 years

age  of lily   = 15 years

______________________________________________

Arranging the list from youngest  to oldest we have

age  of Pam  = 6 years

Age of Tia = 8 years

age  of Veronica   = 11 years

age  of lily   = 15 years

Arranging sisters in order of youngest  to oldest

Pam, Tia, Veronica , Lily

3 0
2 years ago
For flights from a particular airport in January, there is a 30 percent chance of a flight being delayed because of icy weather.
lyudmila [28]

Answer:

0.335

Step-by-step explanation:

1. There is a 30 percent chance of a flight being delayed because of icy weather ,then the probability of being delayed is 0.3 and of being not delayed is 0.7.

2. If a flight is delayed because of icy weather, there is a 10 percent chance the flight will also be delayed because of a mechanical problem, then the probability of being delayed is 0.1 and the probabilty of not being delayed is 0.9.

3. If a flight is not delayed because of icy weather, there is a 5 percent chance that it will be delayed because of a mechanical problem (MP), then the probability of being delayed is 0.05 and the probabilty of not being delayed is 0.95. (See attached probability tree)

Delayed of icy weather - 0.3

Delayed of MP when weather is not icy - 0.7·0.05=0.035

Now, if one flight is selected at random from the airport in January, the probability that the flight selected will have at least one of the two types of delays is

0.3+0.035=0.335

8 0
2 years ago
3. Jacob and Sarah are saving money to go on a trip. They need at least $1975 in order to go. Jacob mows lawns and Sarah walks d
kvv77 [185]
1. The total must be at least $1975:    25x+15y \geq \$1975

2. Dog walks is no more than 4 times lawns: y \leq 4x

3. At least 50 dog walks:  y \geq 50
5 0
2 years ago
A gas company president for a particular city is interested in the proportion of homes heated by gas. Historically, the proporti
Darina [25.2K]

Answer:

p-value (0.0208) is less than alpha = 0.05 reject H0.

Step-by-step explanation:

we have the following data:

sample size = n = 75

x, the number to evaluate is 45

the sample proportion would be: x / n = 45/75

p * = 0.6

Now, the null and alternative hypotheses are:

H0: P = 0.72

Ha: P no 72

two tailed test

statistic tes = z = (p * - p) / [(p * (1-p) / n)] ^ (1/2)

replacing we have:

z = (0.6 - 0.72) / [(0.72 * (1-0.72) / 75)] ^ (1/2)

z = -2.31

p-vaule = 2 * p (z <-2.31)

using z table, we get:

p-vaule = 2 * (0.0104)

p-vaule = 0.0208

Therefore, p-value (0.0208) is less than alpha = 0.05 reject H0.

4 0
2 years ago
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