Suppose pieces of chocolate pie served at a restaurant average 350 calories with a standard deviation of 20 calories. Calories h
ave a Normal distribution due to inexact cutting of the pies. The shaded area represents the proportion of pieces of pie that have more than:__________
1 answer:
Answer:
Step-by-step explanation:
Suppose pieces of chocolate pie served at a restaurant average 350 calories with a standard deviation of 20 calories. Calories have a Normal distribution due to inexact cutting of the pies. Which graph represents the proportion of pieces of pie that have more than 375 calories.
Answer: The z score is used to determine how many standard deviations that the raw score is above or below the mean. If the z score is positive then the raw score is above the mean and for a negative z score means the raw score is below the mean. The z score is given as:
Given that: μ = 350 calories, σ = 20 calories, x > 375
From the graph, The shaded area represents the proportion of pieces of pie that have more than 375 calories
From the normal distribution table, P(x > 375) = P(z > 1.25) = 1 - P(z < 1.25)
= 1 - 0.8944 = 0.1056 = 10.56%
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Answer:
The plot is attached.
Step-by-step explanation:
Plot the function y(x)=e^–0.5x sin(2x) for 100 values of x between 0 and 10. Use a 2- point-wide solid blue line for this function.
The step value for x is (10-0)/100=0.1.
Plot the function y(x)=e–0.5x cos(2x) on the same axes. Use a 3-point-wide dashed red line for this function.
The step value for x is the same as the previous function.
The plot is attached.
Answer:
(1) The degrees of freedom for unequal variance test is (14, 11).
(2) The decision rule for the 0.01 significance level is;
- If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.
- If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.
(3) The value of the test statistic is 0.3796.
Step-by-step explanation:
We are given that you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by models featuring Liz Claiborne's attire with those of Calvin Klein.
The following is the amount ($000) earned per month by a sample of 15 Claiborne models;
$3.5, $5.1, $5.2, $3.6, $5.0, $3.4, $5.3, $6.5, $4.8, $6.3, $5.8, $4.5, $6.3, $4.9, $4.2 .
The following is the amount ($000) earned by a sample of 12 Klein models;
$4.1, $2.5, $1.2, $3.5, $5.1, $2.3, $6.1, $1.2, $1.5, $1.3, $1.8, $2.1.
(1) As we know that for the unequal variance test, we use F-test. The degrees of freedom for the F-test is given by;
Here, = sample of 15 Claiborne models
= sample of 12 Klein models
So, the degrees of freedom = () = (15 - 1, 12 - 1) = (14, 11)
(2) The decision rule for 0.01 significance level is given by;
- If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.
- If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.
(3) The test statistics that will be used here is F-test which is given by;
T.S. = ~
where, = sample variance of the Claiborne models data =
= 1.007
= sample variance of the Klein models data =
= 2.653
So, the test statistics = ~
= 0.3796
Hence, the value of the test statistic is 0.3796.