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Elenna [48]
2 years ago
11

Which fraction is equivalent to StartFraction 2 Over 6 EndFraction? StartFraction 3 Over 7 EndFraction, because StartFraction 2

Over 6 EndFraction = StartFraction 2 + 1 Over 6 + 1 EndFraction = StartFraction 3 Over 7 EndFraction StartFraction 3 Over 9 EndFraction, because StartFraction 2 Over 6 EndFraction = one-third and One-third = StartFraction 3 Over 9 EndFraction StartFraction 3 Over 12 EndFraction, because StartFraction 2 Over 6 EndFraction = one-third and One-third = StartFraction 3 Over 12 EndFraction StartFraction 3 Over 8 EndFraction, because StartFraction 2 Over 6 EndFraction = one-half = StartFraction 2 + 1 Over 6 + 2 EndFraction = StartFraction 3 Over 8 EndFraction
Mathematics
2 answers:
natka813 [3]2 years ago
8 0

Answer:

2/6

Step-by-step explanation:

irinina [24]2 years ago
7 0

Question:

Which fraction is equivalent to \frac{2}{6}?

- \frac{3}{7} because \frac{2}{6}= \frac{2 + 1}{6 + 1}

- \frac{3}{9} because \frac{2}{6}= \frac{1}{3} and \frac{1}{3} = \frac{3}{9}

- \frac{3}{12} because \frac{2}{6}= \frac{1}{3} and \frac{1}{3} = \frac{3}{9}

- \frac{3}{8} because \frac{2}{6}= \frac{1}{2} = \frac{2+1}{6+2} = \frac{3}{8}

Answer:

- \frac{3}{9} because \frac{2}{6}= \frac{1}{3} and \frac{1}{3} = \frac{3}{9}

Step-by-step explanation:

Two fractions are said to be equal if and only if they give the same value when simplified.

The equivalent of \frac{2}{6} is as explained in the selected option;

First, divide numerator and denominator by 2

\frac{2/2}{6/2}

Then simplify

2/2 = 1 and 6/2 = 3; So;

\frac{2/2}{6/2} = \frac{1}{3}

Multiply numerator and denominator by 3

\frac{1*3}{3*3} = \frac{3}{9}

Hence, \frac{2}{6} is equivalent to \frac{3}{9}

You might be interested in
The figure below shows the dimensions of a city park in feet. Shannon thinks the area of city park is 73,084 square feet. Do you
Andreyy89

Answer:

We need to solve for the 4th side

4th side base = 75.5 -60.5 = 10 feet

4th side height = 16

4th side LENGTH^2 = 10^2 + 16^2

4th side = sq root (356) = 18.8679622641

Trapezoid Area = [(sum of the bases) / 2 ] * height

Trapezoid Area = [(136)/2] * 16

Trapezoid Area = 1,088 square feet, which is MUCH smaller

than 73,084

Step-by-step explanation:

3 0
1 year ago
It is 1 1/4 miles from Ahmed’s house to school. How far does Ahmed’s travel in 5 days walking to school and back
Sauron [17]

Ahmed travel 12\frac{1}{2} miles in 5 days walking to school and back.

Step-by-step explanation:

Distance from house to school = 1\frac{1}{4} miles

Distance from school to house = 1\frac{1}{4} miles

Total distance in 1 day = 1\frac{1}{4}+1\frac{1}{4}=\frac{5}{4}+\frac{5}{4}

Total distance in 1 day = \frac{5+5}{4}=\frac{10}{4}

Distance traveled in 5 days = 5*\frac{10}{4}=\frac{50}{4}

Distance traveled in 5 days = \frac{25}{2}=12\frac{1}{2}

Ahmed travel 12\frac{1}{2} miles in 5 days walking to school and back.

Keywords: fraction, addition

Learn more about fractions at:

  • brainly.com/question/10435816
  • brainly.com/question/10435836

#LearnwithBrainly

5 0
2 years ago
Can some one please please help me? solve for x 5 /7x + 1/7 =63 enter your answer in the box below.
Soloha48 [4]
This is confusing but I think yo umean
\frac{x+5}{7x} + \frac{1}{7} =63
times both sides by 7x
x+5+x=441x
2x+5=441x
minus 5 both sides
2x=436
divide both sides by 2
x=218
4 0
1 year ago
Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?
lbvjy [14]

Answer:

x = StartFraction negative

(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction

Step-by-step explanation:

0 = – 3x2 – 2x + 6

It can still be written as

– 3x2 – 2x + 6 =0

Quadratic formula=

-b+or-√b^2-4ac/2a

Where

a=-3

b=-2

c=6

x= -(-2)+ or-√(-2)^2-4(-3)(6)/2(-3)

x = StartFraction negative

(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction

8 0
1 year ago
Perform the indicated operation. (y4 - 1) ÷ (y + 1)
Valentin [98]

The\ domain:\\D:y\neq-1\\\\(y^4-1)\div(y+1)=\dfrac{(y^2)^2-1^2}{y+1}=\dfrac{(y^2-1)(y^2+1)}{y+1}\\\\=\dfrac{(y-1)(y+1)(y^2+1)}{y+1}=(y+1)(y^2+1)=y^3+y^2+y+1\\\\Used:\\(a^n)^m=a^{nm}\\\\a^2-b^2=(a-b)(a+b)

7 0
2 years ago
Read 2 more answers
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