Answer: Real world problem is "A student have c toffee he distribute
th part of those toffees to his friends. He gave total 21 toffees to his friend".
Explanation:
Let a student have c number of toffees in his bag.
It is given that he distribute
th part of those toffees to his friends.
The
th part of c toffees is,

The total number of distributed toffees is 21.

It is the same as given equation.
If we change the equation in words it means the
th part of a number c is 21.
Answer:
Its A
Step-by-step explanation:
i just took the quiz and got it right
If the company makes 1 canoe only, then the cost is, the fixed cost plus how much it costs for the 1 canoe, or
180,000 + 1*120
if it makes 2 canoes
180,000 + 2*120
3 canoes 180,000 + 3*120
4canoes 180,000 + 4*120
x canoes 180,000 + x*120
so... we dunno what "x" is, but whatever "x" maybe, the cost ends up as 180,000 + x*120, or 180,000 + 120x
now, let's see the revenue
1 canoe 1 * 240
2 canoes 2*240
3 canoes 3*240
x canoes x*240
so.. whatever "x" maybe, the Revenue is x*240 or 240x
break-even point is when, the amount of expenses and earnings cancel each other out, or, there's no profit, but there's no loss either, same amount that's spent is also earned back
so, the break-even point occurs when Revenue = Cost
180,000 + 120x = 240x <--- solve for "x"
Answer:
The largest possible area of the deck is 87.11 m² with dimensions;
Width = 9.33 m
Breadth = 9.33 m
Step-by-step explanation:
The area of a given dimension increases as the dimension covers more equidistant dimension from the center, which gives the quadrilateral with largest dimension being that of a square
Given that the railings will be placed on three sides only and the third side will cornered or left open, such that the given length of railing can be shared into three rather than four to increase the area
The length of the given railing = 28 m
The sides of the formed square area by sharing the railing into three while the fourth side is left open are then equal to 28/3 each
The area of a square of side s = s²
The largest possible area of the deck = (28/3)² = 784/9 = 87.11 m² with dimensions;
Width = 28/3 m = 9.33 m
Breadth = 28/3 m = 9.33 m.
7*6*5*4*3*2*1 = 7! = 5040
1*6*5*4*3*2*1 = 6! = 720