The complete problem wants to know the more cost-effective choice is the printing company replaces its press machine every four years.
With this in mind, if they choose Company A, the total amount that needs to be paid to cover 12(4) = 48 months will be
Company A = 9 500 + 48(750) = $13 100
As for Company B, the highest probability of not having any repairs over the four years is 0.32 while there's 0.14 chance that number of repairs will be 3 over the time the contract is applied.
This means that the possible amounts to be paid to Company B are
Company B = 10 500 + 0(150) = $10 500
Company B = 10 500 + 1(150) = $10 650
Company B = 10 500 + 2(150) = $10 800
Company B = 10 500 + 3(150) = $10 950
This shows that choosing the machine from Company B would be better.
Hence, the answer is Company B<span>.</span>
Answer:
5
Step-by-step explanation:
Z = 25/5
in simplest form........
25/5 = 5/1
so the answer is 5.
Answer:
- <em>Between which two tens does it fall?</em><em> </em><u>Between 25 and 26 tens</u>
<em><u /></em>
- <em>Between which two hundreds does it fall?</em> <u>Between 2 and 3 hundreds</u>
Explanation:
The place-value chart is:
Hundreds Tens Ones
2 5 3
<em><u /></em>
<em><u>a) Between which two tens does it fall? </u></em>
Using the place values you can write 253 = 25 × 10 + 3, i.e. 25 tens and 3 ones.
From that you can write:
Then, you conclude that 253 is between 25 and 26 tens.
<u><em>b) Between which two hundreds does it fall?</em></u>
Using the same reasoning:
- 253 = 2 × 100 + 5 × 10 + 3 = 253
Conclusion: 253 is between 2 hundreds and 3 hundreds.
Answer:
1.734
Step-by-step explanation:
Given that:
A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles).
The fitted regression is Time = −7.126 + .0214 Distance
Based on a sample size n = 20
And an Estimated standard error of the slope = 0.0053
the critical value for a right-tailed test to see if the slope is positive, using ∝ = 0.05 can be computed as follows:
Let's determine the degree of freedom df = n - 1
the degree of freedom df = 20 - 2
the degree of freedom df = 18
At the level of significance ∝ = 0.05 and degree of freedom df = 18
For a right tailed test t, the critical value from the t table is :
1.734
To get the square root of 29, we can simply use a
calculator.
So the square root of 29 using the calculator is:
sqrt (29) = 5.3852
<span> So we can say that
5.7145 is greater than the square root of 29.</span>
<span>The difference is 5.7145 – 5.3852 = 0.3293</span>
