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Alecsey [184]
2 years ago
6

You paid $36.20 for a sweater that originally cost $90.50. What percentage of the original price was the sweater on sale for?You

paid $36.20 for a sweater that originally cost $90.50. What percentage of the original price was the sweater on sale for
Mathematics
1 answer:
marin [14]2 years ago
4 0

Answer:

32.761 %

Step-by-step explanation:

Percentage is any fraction or ration expressed as a fraction of 100.

Percentage is calculated using formula

If A has to be expressed as percentage of then it can be expressed as

A/B * 100 in percentage form .

For given problem price paid for sweater = $36.20

original price of sweater = $90.50

Problem is to express percentage of price for which sweater was on sale for.

It can be mathematically  expressed as

what is 36.20% of 90.5

percentage of price for which sweater was on sale for = (price paid for sweater/original price of sweater  ) * 100

It can be mathematically  expressed as

what is 36.20% of 90.5

=>  ($36.20/$90.50 )* 100= 32.761.

32.761 % of the original price sweater was on sale for.

For better understanding ,It can also be said that that if the original price of sweater had been $100, then you would have got it at $32.761 .

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A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.

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Step-by-step explanation:

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Isabel wrote this mystery problem: The quotient is a multiple of 6. The dividend is a multiple of 9. The divisor is s factor of
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A freight company has shipping orders for two products. The first product has a unit volume of 10 cu ft, and it weighs 50 lbs. T
Lady_Fox [76]

Answer:

116 units of the first product

380 units of the second product

Step-by-step explanation:

Product 1 has a unit volume of  10 cu ft

Product 2 has a unit volume of 3 cu ft

The truck has 2300 cu ft of space

Product 1 weighs 50 lbs

Product 2 weighs 40 lbs

The truck can carry 21000 lbs

Let X be the units of product 1

Let Y be the units of product 2

The given information can be expressed as:

10X+3Y=2300...(1)

50X+40Y=21000...(2)

Solving the system of equations:

10X+3Y=2300...(1)

10X=2300-3Y

X=(2300-3Y)/10

Substituting X in (2) we have:

50X+40Y=21000

50[(2300-3Y)/10]+40Y=21000

50[(2300/10)-(3Y/10)]+40Y=21000

50[230-(3Y/10)+40Y=21000

11500-(150Y/10)+40Y=21000

11500-15Y+40Y=21000

11500+25Y=21000

25Y=21000-11500

25Y=9500

Y=380

Substituting Y in (1) we have:

10X+3Y=2300...(1)

10X+3(380)=2300

10X+1140=2300

10X=2300-1140

10X=1160

X=116

So 116 units of the first product and 380 units of the second product can be transported in a single shipment with one truck.

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