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2 years ago

2.) Bob has two weekend jobs. Last weekend he made a total of $77 after

Mathematics

2 answers:

RUDIKE [14]2 years ago

5 0

Answer:

cashier:9 and deliverring newspapers :8

Step-by-step explanation:

aalyn [17]2 years ago

3 0

Answer:

Step-by-step explanation:

x= money earned per hour working as a cashier.

y=money earned per hour working delivering newspapers.

We propose the following system of equations:

5x + 4y =77

6x + 3y=78

We solve the system by reduction method:

-6*(5x+4y=77) ⇒ -30x-24y=-462

5*(6x+3y=78)⇒ 30x+15y=390

---------------------------

-9y=-72 ⇒ y=-72 /-9=8

Now, we get the value of "x" replacing the value of "y" by "8" in any part of the equation above.

5x + 4(8)=77

5x+32=77

5x=77-32

5x=45

x=45/5=9

therefore;

money earned per hour working as a cashier= $9/ hour

money earned per hour working delivering newspapers=$8/hour

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On any given day, mail gets delivered by either Alice or Bob. If Alice delivers it, which happens with probability 1/4 , she doe

Troyanec [42]

Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let X denote delivery time of the mail delivered by Alice and Y denote delivery time of the mail delivered by Bob.

It i provided that:

$X\sim U(9, 11)\\Y\sim U(10, 12)$

The probability that Alice delivers the mail is, p = 1/4.

The probability that Bob delivers the mail is, q = 3/4.

The probability density function of a Uniform distribution with parameters [a, b] is:

$f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Alice is:

$f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Bob is:

$f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.$

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

$f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125$

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

$f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50$

Thus, the value of fₓ (10.5) is 0.50.

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