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leonid [27]
2 years ago
7

Removing which point from the coordinate plane would make the graph a function of x? On a coordinate plane, points are at (negat

ive 2, negative 3), (negative 2, 1), (negative 4, 3), (0, 4), (1, 1), and (2, 3).
Mathematics
2 answers:
Harman [31]2 years ago
6 0

Answer: The first or the second point (- 2, - 3) or (- 2, 1)

Step-by-step explanation:

Ok, a relation (x, y) is a function only if, for each value x in the domain, we have only one value y in the range such that:

f(x) = y.

Here we have the pairs:

(- 2, - 3), (- 2, 1), (- 4, 3), (0, 4), (1, 1), and (2, 3).

Here, for the value x = -2, we have two different values of y.

y = 1 and y = 3.

So this is not a function, then if we want that this relation becomes a function, we must remove the first or the second point.

Semenov [28]2 years ago
4 0

Answer:

<h2>Option<em><u> B.</u></em> is the correct answer.</h2>

Step-by-step explanation:

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Lubov Fominskaja [6]
<h2>Explanation:</h2><h2></h2>

We know that the volume of a prism is defined by:

V=lwh \\ \\ \\ Where: \\ \\ l:length \\ \\ w:width \\ \\ h:height \\ \\ \\ l=\frac{d-2}{3d-9} \\ \\ w=\frac{4}{d-4} \\ \\ h=\frac{2d-6}{2d-4}

Substituting values:

V=\left(\frac{d-2}{3d-9}\right)\left(\frac{4}{d-4}\right)\left(\frac{2d-6}{2d-4}\right) \\ \\ \\ Simplifying: \\ \\ V=\frac{d-2}{3d-9}\cdot \frac{4}{d-4}\cdot \frac{d-3}{d-2} \\ \\ V=\frac{\left(d-2\right)\cdot \:4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)\left(d-2\right)} \\ \\ V=\frac{4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)} \\ \\ V=\frac{4\left(d-3\right)}{3\left(d-3\right)\left(d-4\right)}

Finally: \\ \\  \boxed{V=\frac{4}{3\left(d-4\right)}}

4 0
2 years ago
Read 3 more answers
The area of a small pond is 78.5 yds. What is the diameter of the pond?
Zolol [24]

Answer:

Diameter of pound = 10 yd

Step-by-step explanation:

Given area of circular pond = 78.5 square yd

To find the diameter of the pond.

Solution:

The pond being circular in shape, the area of pond can be given as:

⇒ \pi\ r^2

where r represents radius of the pond.

Thus, we have:

⇒ \pi\ r^2=78.5

Using \pi=3.14

⇒ 3.14r^2=78.5

Solving for r

Dividing both sides by 3.14

⇒ \frac{3.14r^2}{3.14}=\frac{78.5}{3.14}

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Taking square root both sides.

⇒ \sqrt{r^2}=\sqrt{25}

⇒ r=\pm5

So, radius = 5 yd, as distances are always positive.

Diameter = 2\times radius=2\times 5\ yd= 10\ yd

Thus, diameter of pound = 10 yd

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2 years ago
50% of all the cakes Lucy bakes that week were party cakes 1-5 fruit cakes and remainder were sponge cakes what percentage of ca
Stells [14]

30% were sponge cakes because you do 1/5=0.2 or20%+50%=70% and 100%-70%=30% so 30% is your answer.
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We read off Z= 0.25 from the normal distribution table

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