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maks197457 [2]
1 year ago
13

The graph shows the increase of cost of strawberries per pound in dollars, y, over a period of years, x. What is the rate of inc

rease of the cost of strawberries per pound?

Mathematics
2 answers:
vfiekz [6]1 year ago
7 0

Answer:

A) $0.50

Step-by-step explanation:

wel1 year ago
6 0

Answer:

the answer is $0.50

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2x-10/4=3x<br> −10<br> −1<br> 2<br> 11
evablogger [386]

Answer:

<h2>-1</h2>

Step-by-step explanation:

\dfrac{2x-10}{4}=3x\qquad\text{multiply both sides by 4}\\\\2x-10=12x\qquad\text{subtract}\ 2x\ \text{from both sides}\\\\-10=10x\qquad\text{divide both sides by 10}\\\\-1=x\to x=-1

6 0
2 years ago
In ΔMNO, the measure of ∠O=90°, ON = 65, MO = 72, and NM = 97. What is the value of the tangent of ∠M to the nearest hundredth?
PilotLPTM [1.2K]

Answer:

Therefore the value of tangent of ∠M is 42°.

Step-by-step explanation:

Given that,

                  In ΔMNO, ∠O=90°, ON=65, MO=72, and NM=97.

and we have to find the value of tangent of ∠M.

Diagram of the given triangle is shown below:

Now,

ΔMNO is a right angle triangle, so we can use all the trigonometric ratio.

sin\alpha =\frac{Perpendicular}{Hypotenuse}

cos\alpha =\frac{Base}{Hypotenuse}

tan\alpha =\frac{sin\alpha }{cos\alpha } = \frac{Perpendicular}{Base}

tangent of ∠M = \frac{Perpendicular}{Base}

                         = \frac{ON}{MO}

                         = \frac{65}{72}

                         = 0.90278

∴∠M = tan^{-1} (0.90278)

        = 42.0750° ≅ 42°

Therefore the value of tangent of ∠M is 42°.

4 0
2 years ago
Sarah wants to study the time it takes to complete a lab in a regular biology course compared to the time it takes to complete a
Tcecarenko [31]
Just did it...its the first one...second one....fifth one and sixth one...that..is if your on edegenuity..
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2 years ago
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Shelia is dividing x4 – 4x3 + 4x2 – 6x + 5 by x – 1 using a division table. Quotient Divisor x3 – 3x2 + x – 5 x x4 –3x3 x2 A – 1
Hatshy [7]
Is there by answer choice? Or by a table?
4 0
1 year ago
What are the domain, range, and asymptote of h(x) = 6x – 4? domain: {x | x is a real number}; range: {y | y &gt; 4}; asymptote:
Mkey [24]

Answer:

Step-by-step explanation:

The domain of a function is the set for which the function is defined. Our function is the function h(x) = 6x-4. This function is defined regardless of the value of x, so it is defined for every real value of x. That is, it's domain is the set {x|x is a real number}.

The range of the function is the set of all possible values that the function might take, that is {y|y=6x-4}. Recall that every real number y could be written of the form y=6x-4 for a particular x. So the range of the function is the set {y|y is a real number}.

Note that as x gets bigger, the value of 6x-4 gets also bigger, then it doesn't approach any particular number. Note also that as x approaches - infinity, the value of 6x-4 approaches also - infinity. In this case, we don't have any horizontal asymptote. Since the function is defined for every real number, it doesn't have any vertical asymptote. Since h is a linear function, it cannot have any oblique asymptote, then h doesn't have any asymptote.

4 0
1 year ago
Read 2 more answers
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