A . r^(3-1) = 18
a . r^2 = 18...... (i)
a . r^(6-1) = 486
a . r^5 = 486 ...... (ii)
dengan membuat perbandingan dari kedua persamaan diperoleh:
r^2/r^5 = 18/486
1/r^3 = 1/27
r^3 = 27
r = akar pangkat 3 dari 27
r = 3
dari persamaan <span>a . r^2 = 18...... (i)
a . 3^2 = 18
a . 9 = 18
a = 18/9 = 2</span>
Step-by-step explanation:
Given equaiton is in the form of ax^2 +bx+c=0
we apply quadratic formula to solve for x
a= 1 b = -12 and c= 59
Divide the 12 and square root terms by 2
so 
and 
Answer:
where the point B lie ,first say point B where lie
Step 1
<u>Find the measure of angle x</u>
we know that
If ray NP bisects <MNQ
then
m<MNQ=m<PNM+m<PNQ ------> equation A
and
m<PNM=m<PNQ -------> equation B
we have that
m<MNQ=(8x+12)°
m<PNQ=78°
so
substitute in equation A
(8x+12)=78+78-------> 8x+12=156------> 8x=156-12
8x=144------> x=18°
Step 2
<u>Find the measure of angle y</u>
we have
m<PNM=(3y-9)°
m<PNM=78°
so
3y-9=78------> 3y=87------> y=29°
therefore
<u>the answer is</u>
the measure of x is 18° and the measure of y is 29°
a cylinder and a cone. the cone would go on the top, and the cylinder on the bottom.
