What is the result of anding 255 and 15?

You are buying boxes of cookies at a bakery. Each box of cookies costs \$4$4dollar sign, 4. In the equation below, ccc represent

Basile [38]

Answer:

The required equation is

d = 4c

where d represents the cost of cookies in dollar and c represents the number of boxes of cookies.

Step-by-step explanation:

Given that, the cost of each box of cookies is $4.

It means,

The cost of 1 box of cookies is $4.

The cost of 2 boxes of cookies is $(4+4) =$(2×4)

The cost of 3 boxes of cookies is $(4+4+4) =$(3×4)

The cost of cookies

=(Number of boxes × 4)

The required equation is

d = 4c

where d represents the cost of cookies in dollar and c represents the number of boxes of cookies.

8 0

2 years ago

Bruce wants to make 50 ml of an alcohol solution with a 12% concentration. He has a 10% alcohol solution and a

Ira Lisetskai [31]

Answer:

0.1x+0.15(50-x)= 50*0.12

Step-by-step explanation:

50 ml of 12% solution has 50*0.12 ml of alcohol

x ml of 10% solution has x*0.1 ml of alcohol

(50-x) ml of 15% solution has (50-x)*0.15 ml of alcohol

The equation to solve is:

0.1x+0.15(50-x)= 50*0.12

3 0

2 years ago

A hole is drilled in a sheet-metal component, and then a shaft is inserted through the hole. The shaft clearance is equal to dif

VashaNatasha [74]

Answer:

(A)

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

0 otherwise.

Step-by-step explanation:

(A)

We are looking for the probability that the random variable X is greater than 0.8.

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

For any $x$ you are looking for the probability $P(X \geq x)$ which is

$P(X \geq x) = \int\limits_{-\infty}^{x} 1.25(1-t^4) dt = \int\limits_{0}^{x} 1.25(1-t^4) dt = 1.25x - 0.25x^2$

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

0 otherwise.

5 0

2 years ago

In the diagram, transversal t cuts across the parallel lines a and b. Match the pairs of angles with the relationship that shows

charle [14.2K]

we know that

case a) alternate exterior angles

m∠2=m∠7 --------> by alternate exterior angles

m∠1=m∠8 --------> by alternate exterior angles

case b) alternate interior angles

m∠3=m∠6 --------> by alternate interior angles

m∠5=m∠4 --------> by alternate interior angles

case c) corresponding angles

m∠1=m∠5 --------> by corresponding angles

m∠3=m∠7 --------> by corresponding angles

m∠2=m∠6 --------> by corresponding angles

m∠4=m∠8 --------> by corresponding angles

case d) vertical angles

m∠1=m∠4 --------> by vertical angles

m∠2=m∠3 --------> by vertical angles

m∠5=m∠8 --------> by vertical angles

m∠6=m∠7 --------> by vertical angles

therefore

the answer in the attached figure

5 0

2 years ago

A furnace used 40% of the fuel in its tank in the month of March and then used 25% of the remaining fuel in the month of April.

gtnhenbr [62]

March: 240 * 0.4 = 96 used
240 - 96 = 144 remains in the tank

April : 144 * 0.25 = 36 used
144 - 36 = 108 remains in tank

answer: 108 gallons left at the end of April

6 0

2 years ago