From the table, the speed of Corinne is given by
From the graph, the speed of Aretha is given by
The distance from the starting point of Corinne at any time t is given by D = 0.125t while the distance from the starting point of Aretha at any time t is given by D = 3.5 + 0.1t
Let t be the number of minutes after the start of the race when Corinne catchs Aretha, then
0.125t = 3.5 + 0.1t
0.025t = 3.5
t = 3.5 / 0.025 = 140
Therefore, the number of <span>minutes after the start of the race that Corinne will catch Aretha</span> is 140 minutes.
Answer : (13)
Let x be the number of party favors in each (27 boxes)
Let y be the number of favors in last box
Given : total of party favors = 1552
27 boxes + last box = 1552
27x + y = 1552
We divide 1552 by 27, the quotient will be our x and the remainder will be y(number of party favors in last box)
Use long division
= 57 and remainder is 13
the number of party favors in each of (27 boxes) = 57
the number of party favors in last box = 13
So, there are 13 party favors in last box.
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Let's call the number x. Now, let's make an equation to help us solve this problem.
(((0.43+x)-.58)-4.04) = 30.3
(0.43+x)-4.64 = 30.3
x-4.21 = 30.3
x = 30.3 + 4.21
x = 34.51
The answer is 34.51 and there's the work for you. Have a great day!
Answer: she needs to buy 80kg of
dark chocolate and 70kg of milk chocolate.
Step-by-step explanation:
Let d represent the number of kilograms of dark chocolate that she buys.
Let m represent be the number of kilograms of milk chocolate that she buys.
She wants to buy 10g more of dark chocolate than milk chocolate. This means that
x = y + 10
She needs 150kg of chocolate in total for her next order. This means that
x + y = 150 - - - - - - - - - - - --1
Substituting x = y + 10 into equation 1, it becomes
y + 10 + y = 150
2y + 10 = 150
2y = 150 - 10 = 140
y = 140/2 = 70
x = y + 10 = 70 + 10
x = 80
Answer: ± 1.96
Step-by-step explanation:
Given the following :
Mean (m) time spent = 11.85
Standard deviation = 4 minutes
Since the population of site visits is Normally distributed, Hence, the test statistic will follow a normal distribution :
The test the hypothesis that mean time has changed at 0.05 confidence interval
Normal distributions have a mean value of 0 and standard deviation of 1
Using a two tailed test At 0.05 confidence interval ;
Using the critical value calculator, which in general under normal distributions :
0.05% confidence interval for a two tailed test is
± 1.96
