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kolbaska11 [484]
2 years ago
13

The drama club members at Millie’s middle school are selling tickets to the school play. Millie wants to determine the average n

umber of tickets sold. First, she surveyed the club members in her homeroom, and then she surveyed every third member of the club in her physical education class. Which sampling technique should produce a more representative sample? 1.Both samples should be exactly the same. 2.Neither sample will be representative. 3.The first sampling method, surveying drama club members in her homeroom, is the most representative. 4.The second sampling method, surveying drama club members in her physical education class, is the most representative.
Mathematics
2 answers:
loris [4]2 years ago
5 0

Answer:

If you looking for the answer in the first answer its the<em><u> fourth option</u></em>

I recommend not to waste your time

White raven [17]2 years ago
3 0
The first sampling method is Convenient Sampling. It is biased sampling and it is not representative of a random sample.

The second sampling method is Systematic Sampling. If this method of sampling is drawn from the population, it is an efficiently randomized sampling method.

Let us review the given answers.

1. Both samples should be exactly the same.
   INCORRECT

2. Neither sample will be representative.
   Because the second sampling method can be random, this answer is
   INCORRECT.

3. The first sampling method, ..., is the most representative,
   INCORRECT

4. The second sampling method, ..., is the most representative.
    CORRECT
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Given △DEF, which is not equal to cos(F)? sin(F). sin(D). tan(F). cos(D)
valentina_108 [34]

Answer: The correct option is tan(F).

Explanation:

In the given figure the triangle is a right angle triangle because \angle E=90^{\circ}.

It is also given that DE=EF=5 and DF=5\sqrt{2}.

Since it is an isosceles right angle triangle, therefore the value of perpendicular and base is same for both angles D and F, which is 5.

\cos (F)=\frac{Base}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of cos(F) is \frac{1}{\sqrt{2}}.

\sin (F)=\frac{Perpendicular}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of sin(F) is \frac{1}{\sqrt{2}}.

\sin (D)=\frac{Perpendicular}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of sin(D) is \frac{1}{\sqrt{2}}.

\tan (F)=\frac{Perpendicular}{Base}=\frac{5}{5} =1

The value of tan(F) is 1. Which is not equal to \frac{1}{\sqrt{2}}.

\cos (D)=\frac{Base}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of cos(D) is \frac{1}{\sqrt{2}}.

Therefore, the value of tan(F) is not equal to the value of cos(F), so the correct option is third.

3 0
2 years ago
Read 2 more answers
The speed of sound is approximately 340 m / s. How long will it take for the sound to travel from the batter to a spectator who
iris [78.8K]
The first answer is 3/34 sec and the second answer is 15/34 sec.

Set up a proportion for these problems.  For the first question,
340/1 = 30/x

Cross multiply:
340*x = 1*30
340x = 30

Divide both sides by 340:
340x/340=30/340
x = 30/340 = 3/34

For the second question,
340/1 = 150/x

Cross multiply:
340*x = 150*1
340x=150

Divide both sides by 340:
340x/340 = 150/340 
x = 150/340 = 15/34
4 0
2 years ago
What is the domain of validity for csctheta =start fraction 1 over sine theta end fraction? (1 point) all real numbers all real
dem82 [27]
We know the following relationship:

csc(\theta)=\frac{1}{sin(\theta)}

The domain of a function are the inputs of the function, that is, a function f is a relation that assigns to each element x in the set A exactly one element in the set B. The set A is the domain (or set of inputs) of the function and the set B contains the range (or set of outputs).Then applying this concept to our function csc(\theta) we can write its domain as follows:

1. D<span>omain of validity for csc(\theta):
</span>
D: \{\theta \in R/ sin(\theta) \neq 0 \} \\ In words: All \ \theta \ that \ are \ real \ values \ except \ those \ that \ makes \ sin(\theta)=0 
 
When:

sin(\theta)=0?

when:

\theta=..., -2\pi,-\pi,0,\pi,\2pi,3pi,...,k\pi

where k is an integer either positive or negative. That is:

sin(k\theta)=0 \ for \ k=...,-2,-1,0,1,2,3,...

To match this with the choices above, the answer is:

<span>"All real numbers except multiples of \pi"

</span>
2. which identity is not used in the proof of the identity 1+cot^{2}(\theta)=csc^{2}(\theta):

This identity can proved as follows:

sin^2{\theta}+cos^{2}(\theta)=1 \ Dividing \ by \ sin^{2}(\theta) \\ \\ \therefore \frac{sin^2{\theta}}{sin^{2}(\theta)}+\frac{cos^{2}(\theta)}{sin^{2}(\theta)}=\frac{1}{sin^{2}(\theta)} \\ \\ \therefore 1+cot^{2}(\theta)=csc^{2}(\theta)

The identity that is not used is as established in the statement above:

<span>"1 +cos squared theta over sin squared theta= csc2theta"

Written in mathematical language as follows:

</span>\frac{1+cos^{2}(\theta)}{sin^{2}(\theta)}=csc^{2}(\theta)<span>


</span>
4 0
2 years ago
Read 2 more answers
Jarvis works in a garage £6 an hour. If he works on Saturday, he is paid time and a quarter. If he works on Sunday, he is paid t
ruslelena [56]

Answer: He is paid $90 last weekend.

Step-by-step explanation:

Since we have given that

Amount he earns per hour = $6

If he works on Saturday, he is paid time and a quarter .

Amount would be

6\times 1.25=\$7.5

If he works on Sunday, he is paid time and a half.

Amount would be

6\times 1.5=\$9

Number of hours he worked on Saturday = 6 hours

Number of hours he worked on Sunday = 5 hours

So, Total amount he is paid last weekend altogether is given by

6\times 7.5+5\times 9\\\\=\$90

Hence, he is paid $90 last weekend.

4 0
2 years ago
Lisa the numbers least to greatest -2/5 -2.47 -2 1/2 5 21/4
Paraphin [41]

Answer:

least to greatest are:

-2.5, -2.47, -2/5, 5, 21/4

3 0
2 years ago
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