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Svetach [21]
1 year ago
12

A farmer sells 6.5 kilograms of pears and apples at the farmer's market. 3/4 of this weight is pears, and the rest is apples. Ho

w many kilograms of apples did she sell at the farmers market?
Mathematics
2 answers:
Jet001 [13]1 year ago
8 0

Answer:

1.625 kilograms

Step-by-step explanation:

Since total weight of pears and apples is 6.5 kilograms and 3/4 of this weight is pears, the weight of the pears is

→ 6.5 x 3/4 = 4.875 kilograms

Since the weight of the pears is 4.875, we can subtract it from the total weight to find the weight of the apples

→ 6.5 - 4.875 = 1.625 kilograms

uranmaximum [27]1 year ago
3 0

Answer:

1.625 kg

Step-by-step explanation:

Total weight sold by the farmer =6.5 kilograms

If 3/4 of the weight is pears:

Weight proportion of apple=1-\frac{3}{4}= \frac{1}{4}

Therefore:

Weight of Apples sold at the market = \frac{1}{4} X 6.5 kg\\

=1.625 kg

The farmer sold 1.625 kilograms of apple.

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J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
2 years ago
Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the so
Georgia [21]
In order to construct this equation, we will use the variables:
V to represent mixture volume (40 ml)
C to represent mixture concentration (0.32)
v₁ to represent volume of first solution (40 / 4 = 10 ml)
c₁ to represent concentration of first solution (0.2)
v₂ to represent the volume of the second solution (40 * 3/4 = 30 ml)
c₂ to represent the concentration of the second solution 


We know that the total amount of substance, product of the volume and concentration, in the final solution is equal to the individual amounts in the two given solutions. Thus:
VC = v₁c₁ +  v₂c₂
40(0.32) = 10(0.2) + 30c
6 0
2 years ago
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Davi has 75 flower seeds. He wants to plant the seeds in pots so that every seed is planted, and every pot has
Vlada [557]

Answer:

15 pots

Step-by-step explanation:

If you divide 75 by 5 then you get 15. So if you plant 5 seeds per pot then you will need 15 pots to plant all of the seeds.

Hope this is what you wanted.

4 0
2 years ago
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Camille knew that a triangle had one side with a length of 16 inches and another side with a length of 20 inches. She did not kn
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The unknown side is 9. Because 9 x 5= 45, 45 being the perimeter, that is 5 times the unknown side. And 45 is the sum of 9, 16, and 20.
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2 years ago
David is making rice for his guests based on a recipe that requires rice, water, and a special blend of spice, where the rice-to
steposvetlana [31]

Answer:

  8 servings

Step-by-step explanation:

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  40 g/(5 g/serving) = 8 servings

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2 years ago
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